小编and*_*imo的帖子

当我编译这段代码时,当我选择A时,它会导致scanf要求两次值.我在这里缺少什么？

这不是第一次遇到这种情况,所以我怀疑我没有抓住scanf的基本内容.

#include <stdio.h>
#include <stdlib.h>

int main()
{

char choice;
printf("1. 'enter 'A' for this choice\n");
printf("2. 'enter 'B' for this choice\n");
printf("3. 'enter 'C' for this choice\n");

scanf("%c", &choice);

switch (choice)
{
case 'A':
    {
        int a =0;
        printf("you've chosen menu A\n");
        printf("enter a number\n");
        scanf("%d\n", &a);
        printf("%d\n", a);
    }
break;
case 'B':
printf("you've chosen B\n");
break;
case 'C':
printf("you've chosen C\n");
break;
default:
printf("your choice is invalid\n!");
break;
}

return 0;

}