小编Maz*_*azi的帖子

常规静态分配数组如下所示，可以使用以下公式进行访问：

const int N = 3;
const int M = 3;

int a1[N][M] = { {0,1,2}, {3,4,5}, {6,7,8} };

int x = a1[1][2]; // x = 5 
int y = *(a1+2+N*1); // y = 5, this is what [] operator is doing in the background

数组是连续的内存区域。在动态数组分配的情况下看起来有所不同，而是有指向数组的指针数组：

int** a2 = new int*[N];
for (int i = 0; i < N; i++) 
   a2[i] = new int[M];

//Assignment of values as in previous example

int x = a2[1][2];
int y = *(*(a2+1))+2); // …