小编Clo*_*dID的帖子

我想将其他编码中的数据转换为UTF-8.我陷入了以下问题:

1. 执行附加的代码给我:pointer being freed was not allocatediconv().为什么iconv与我的记忆一起玩？
2. 当我不自由(dst)它不会崩溃但没有打印.甚至没有胡言乱语.怎么了？

void utf8(char **dst, char **src, const char *enc)
{
    iconv_t cd;
    size_t len_src,
           len_dst;

    len_src = strlen(*src);
    len_dst = len_src * 8; // is that enough for ASCII to UTF8?

    cd = iconv_open("UTF-8", enc);

    *dst = (char *)calloc(len_dst+1, 1);

    iconv(cd, src, &len_src, dst, &len_dst);
    iconv_close(cd);
}

int main(int argc, char **argv)
{
    char *src = "hello world";
    char *dst;

    utf8(&dst, &src, "ASCII");
    printf("%s\n", dst);

    free(dst);
    return 0;
}

如何从字符串中获取具有最大ascii值的char？

$str = 'abcb'
# extract biggest char somehow
# as a result $char contains "c"