小编Jos*_*ick的帖子

我正在使用Laravel 5.1和Guzzle发送API请求.

我有两个函数,一个用于获取一个人,另一个用于检索有关该人的数据,因为每个函数都是一个单独的请求.

如果没有找到任何404响应代码被发回并由laravel拾取.

然而,来自函数1的404响应与来自函数2的响应具有不同的含义,即使它们是相同的响应代码和异常而是guzzle.

我试图在方法的控制器中捕获错误,希望它会在laravels异常处理程序之前捕获它,但它似乎不起作用并被处理程序捕获.

如何在Laravels异常处理程序之前在控制器中捕获异常？

我有一组以这种格式返回的图像文件名。

这是存储文件名的 $this->images 的 var_dump()

 array (size=9)
0 => 
object(stdClass)[8]
  public 'filename' => string '1416073696I0QHU.jpg' (length=19)
  public 'primary' => string '1' (length=1)
1 => 
object(stdClass)[9]
  public 'filename' => string '1416073696cTU23.jpg' (length=19)
  public 'primary' => string '0' (length=1)
2 => 
object(stdClass)[10]
  public 'filename' => string '1416073696uxsvq.jpg' (length=19)
  public 'primary' => string '0' (length=1)
3 => 
object(stdClass)[11]
  public 'filename' => string '1416073696uBYgo.jpg' (length=19)
  public 'primary' => string '0' (length=1)
4 => 
object(stdClass)[12]
  public 'filename' => string '1416073696vLBiH.jpg' (length=19)
  public 'primary' => string …

我正在尝试显示存储在/ resources/assets/img/champions /中的图像

同

     <img class="img-rounded"
           src="{{asset("/resources/assets/img/champions/Ahri.png")}}"
                style="width:32px;height:32px;">

这给了我这个输出

<img class="img-rounded" 
src="http://localhost:8000/resources/assets/img/champions/Ahri.png" style="width:32px;height:32px;">

据我所知,这应该显示图像对吗？

这样去浏览器中的路径

http://localhost:8000/resources/assets/img/champions/Ahri.png

给我

NotFoundHttpException in compiled.php line 8140:

嗨我有一组获取数据的查询

当天有两个计数行,晚上有两个,我想要的是将这些组合成一个查询.

SELECT controllerID
    ,COUNT(CardID) AS GoodCountDay
FROM ReaderData
WHERE (
        ReaderTime BETWEEN '08:00:00'
            AND '20:00:00'
        )
    AND (CardID = 'fffffff0')
    AND (DATEDIFF(DAY, DATEADD(DAY, - 0, CURRENT_TIMESTAMP), dtReading) = 0)
GROUP BY controllerID

SELECT controllerID
    ,COUNT(CardID) AS ScrapCountDay
FROM ReaderData
WHERE (
        ReaderTime BETWEEN '08:00:00'
            AND '20:00:00'
        )
    AND (CardID = '007CF00B')
    AND (DATEDIFF(DAY, DATEADD(DAY, - 0, CURRENT_TIMESTAMP), dtReading) = 0)
GROUP BY controllerID

SELECT controllerID
    ,COUNT(CardID) AS GoodCountNight
FROM ReaderData
WHERE (dtReading >= DATEADD(hour, 20, DATEADD(day, - 1, CAST(CAST(GETDATE() …

我在SQL Server中有一个查询,检查数据是否已经存在于数据库中,如果数据不存在,那么它会将数据插入数据库.

这是我的查询:

IF EXISTS
(SELECT 
    DocumentNo,
    DocumentDate,
    CustomerAccountName,
    PostalName,
    RequestedDeliveryDate,
    SupplierDocumentNo,
    SupplierAccountName,
    DispatchName
 FROM 
    SalesOrders
 WHERE 
    (DocumentNo = '0000233555'))
    UPDATE SalesOrders
    SET RequestedDeliveryDate ='2015-04-16',
        SupplierDocumentNo ='',
        SupplierAccountName = '',
        DispatchName =''
    WHERE 
        (DocumentDate = '0000233555') 

ELSE

    INSERT INTO SalesOrders (DocumentNo, DocumentDate, 
                             CustomerAccountName, PostalName, 
                             RequestedDeliveryDate, SupplierDocumentNo, 
                             SupplierAccountName, DispatchName)
    VALUES ('0000233555', '2015-03-05',
            'Company name', 'Company name',
            '2015-04-16', '',
            '', '')

但是我得到了这个错误.

消息241,级别16,状态1,行12
转换从字符串转换日期和/或时间时失败.

这是表格的设计方式.

        column name          Data type      Allow Null
              ID                int         Unchecked
        DocumentNo           varchar(50)    Checked
        DocumentDate           date         Checked
        CustomerAccountName  varchar(100) …