我有两个 XML 文件：
<!------------------------File1--------------------------------->
<note id="ignoreThisAttribute_1">
<to>Experts</to>
<from>Matrix</from>
<heading id="dontIgnoreThisAttribute_1">Reminder</heading>
<body>Help me with this problem</body>
</note>
<!------------------------File2--------------------------------->
<note id="ignoreThisAttribute_2">
<to>Experts</to>
<from>Matrix</from>
<heading id="dontIgnoreThisAttribute_2">Reminder</heading>
<body>Help me with this problem</body>
</note>
在比较这两个文件时，我必须忽略idNode: 的属性： 。note
我在用DiffBuilder：
Diff documentDiff = DiffBuilder.compare(srcFile).withTest(destFile).build()
大多数在线解决方案建议实施DifferenceEvaluator：
也尝试过，但这会忽略具有属性 id 的所有节点，而我想忽略特定节点的属性：
Diff documentDiff = DiffBuilder.compare(srcFile).withTest(destFile).build()
在我的测试类中调用方法：
public class IgnoreAttributeDifferenceEvaluator implements DifferenceEvaluator {
private String attributeName;
public IgnoreAttributeDifferenceEvaluator(String attributeName) {
this.attributeName = attributeName;
}
@Override
public ComparisonResult evaluate(Comparison comparison, ComparisonResult outcome) {
if (outcome …