小编rah*_*001的帖子

我正在尝试调整我的反应原生应用程序中的图像(较小以适应屏幕),但由于它太大而无法执行此操作.

这是代码:

'use strict';

var React = require('react-native');
var {
  StyleSheet,
  Text,
  TextInput,
  View,
  TouchableHighlight,
  ActivityIndicatorIOS,
  Image,
  Component
} = React;

var styles = StyleSheet.create({
  description: {
    marginBottom: 20,
    fontSize: 18,
    textAlign: 'center',
    color: '#656565'
  },
  container: {
    padding: 30,
    marginTop: 65,
    alignItems: 'center'
  },
  flowRight: {
    flexDirection: 'row',
    alignItems: 'center',
    alignSelf: 'stretch'
  },
  buttonText: {
    fontSize: 18,
    color: 'white',
    alignSelf: 'center'
  },
  button: {
    height: 36,
    flex: 1,
    flexDirection: 'row',
    backgroundColor: '#48BBEC',
    borderColor: '#48BBEC',
    borderWidth: 1,
    borderRadius: 8,
    marginBottom: …

授权并从服务获取令牌后我收到错误并继续收到以下错误:

    RCTJSLog> "encountered an error loading page",
 {"target":19,"canGoBack":false,"domain":"WebKitErrorDomain","code":102,"loadi

ng":false,"title":"","canGoForward":false,"description":"Frame load 

interrupted","url":""} 

知道这意味着什么吗？它正在跳过Web视图,因为我已经过身份验证但是给了我一个错误屏幕.

这是GIT

LinkingIOS说:
*iOS模拟器不支持mailto:和tel:模式*因为没有安装邮件和电话应用程序 - 您需要在设备上测试*它们.

当点击电子邮件地址时,我可以在我的React Native应用程序中使用什么链接到本机Mail应用程序？同样,如果点击电话号码,如何选择拨打电话或短信？

我正在创建一个非常轻量级的搜索功能,它具有以下功能:

if (searchStr == people.first_name ||
    searchStr == people.last_name || 
    searchStr == people.job || 
    searchStr == people.skills.forEach(function(x) { return x })) {
  Results.push(people)
}

searchStr是搜索字符串; 'people'是一个人对象,只有一个名字和一个姓名和一个作业,但只有一个数组是people.skills - 无论如何,我可以在if-conditional中以匿名方式遍历该数组功能？

我是python的新手,并尝试创建一个tictactoe游戏来学习语法并继续遇到缩进问题.我的理解是,只要空格是一致的,那么程序应该运行？这是代码:

board = [ 
            ['|', '|', '|' ],
            ['|', '|', '|'],
            ['|', '|', '|'] 
        ] 

player1 = ''
player2 = ''


def tictactoe ():

    player1 = raw_input('What is player one name?')
    print(player1)
    player2 = raw_input('What is player two name?')
    print(player2)



def getMove ():
# get move and pass it to testMove

def getMove ():
# get move and pass it to testMove

# def testMove():
# test for moves and pass to make move

# def makeMove ():
#make move …

我试图验证一个用户名和密码,当有一个发布请求时,它不是null,这样就没有empy行,但我不断得到

Express server listening on port 5000

/Users/ra/Desktop/Jos/node_modules/sequelize/lib/dao-validator.js:216
      throw new Error("Invalid validator function: " + validatorType)
            ^
Error: Invalid validator function: allowNull

继承人的雇主模式

'use strict';

var Sequelize = require('sequelize');

module.exports = function (sequelize) {
    var Employer = sequelize.define("employer", {
        username: { type: Sequelize.STRING, validate: { allowNull: false } },
        password: { type: Sequelize.STRING, validate: { allowNull: false } }
    });
    return {
        Employer: Employer
    };
};