我有一个文件，该文件按此顺序包含3行：
bsub -I -q vtran "vtran -scan_pad 0X ../test/pm30_60_224_jtag_bist_full_vector_off.vtran"
bsub -I -q vtran "vtran -scan_pad 0X ../test/pm30_60_224_jtag_bist_full_vector_on.vtran"
bsub -I -q vtran "vtran -scan_pad 0X ../test/pm30_60_224_jtag_bist_sanity_dft.vtran"
我必须按以下顺序逐一执行unix命令行中的所有行：
bsub -I -q vtran "vtran -scan_pad 0X ../test/pm30_60_224_jtag_bist_sanity_dft.vtran"
bsub -I -q vtran "vtran -scan_pad 0X ../test/pm30_60_224_jtag_bist_full_vector_off.vtran"
bsub -I -q vtran "vtran -scan_pad 0X ../test/pm30_60_224_jtag_bist_full_vector_on.vtran"
如何使用单个命令行重新排列和执行所有3个命令？
我已经按照您的建议进行了尝试：
line1: echo start
line2: bsub -I -q vtran "vtran -scan_pad 0X ../test/pm30_60_224_jtag_bist_sanity_dft.vtran"
line3: echo hello
line4: bsub -I -q vtran "vtran -scan_pad 0X ../test/pm30_60_224_jtag_bist_full_vector_off.vtran"
line5: echo bye
line6: …我有一个包含值的数组.我需要从每个数组元素中减去1并保存它自己.
例如:
chop $tve_005;
@words = split (/,/, $tve_005);
现在@words包含:
524210
1713409
311919
1422134
16658312
但是在其余代码中需要使用的实际值是:(总是减去1)
524209
1713408
311918
1422133
16658311
如何减去并保存相同的数组.