我正在研究一些按位运算符,我想提取数字的最后16位二进制数字并对它们进行操作.我基本上想要看到像0xFFFFFFFF这样的负数,然后提取LSB FFFF并将它们连接起来,0这样我最终得到一个零,所以它看起来像0x0000FFFF.我只关心较小的负数,所以LSB应该是我需要的所有信息.
这是我在C中的方法:
#include <stdio.h>
int main(){
int a = -1, c = 0;
short b = (short)a;
printf("a is %x\nb is %x",a,b);
c = (0 << 16) | b;
printf("\nc is %x\n", c);
return 0;
}
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我的思维过程是,我可以在我转换int a到一个较短,使得它看起来像FFFF,而不是FFFFFFFF我将有一个更好的时间.对我来说不幸的是,这只是打印出ffffffff变量
我有一个函数可以在Visual Studio中执行我想要的操作,我将它转移到GCC以确保一切都在那里工作.
我现在因使用该std::find函数而产生了大量的编译错误.
我希望有人可以看看并帮助我找出为什么我只在GCC中收到这些错误.以下是代码示例:http://cpp.sh/6pky
// Example program
#include <iostream>
#include <string>
#include <vector>
#include <list>
#include <utility>
using namespace std;
int main()
{
vector < list < pair <string, string> > > v;
v.resize(15);
pair<string, string> k ("foo", "bar");
auto & whichList = v[2];
if(find(begin(whichList), end(whichList), k) != end(whichList))
cout << "true";
}
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有问题的部分是find(begin(whichList), end(whichList), k).
我收到一个错误,说我无法比较一对配对列表(我本周一直在处理的问题),我理解.我很好奇为什么VS2015不仅不识别这个错误,而且还适当地执行任务.
Hey I have a fairly simple question that some quick google searches couldnt solve so I'm coming here for some help.
I'm having trouble just getting my assignment off the ground because I can't even write the skeleton code!
Basically I have a header file like so:
namespace foo{
class A {
public:
class B {
B();
int size();
const int last();
};
};
}
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And I want to know how to refer to these guys outside of the file …
c++ implementation templates scope-resolution data-structures
我正在尝试制作嵌套数组的副本,并且似乎我继续通过我的尝试进行参考。
更具体地说,我试图拥有一个数组数组,其中每个子数组都建立在前一个数组上。这是我的尝试:
#!/usr/bin/perl -w
use strict;
use warnings;
my @aoa=[(1)];
my $i = 2;
foreach (@aoa){
my $temp = $_;#copy current array into $temp
push $temp, $i++;
push @aoa, $temp;
last if $_->[-1] == 5;
}
#print contents of @aoa
foreach my $row (@aoa){
foreach my $ele (@$row){
print "$ele ";
}
print "\n";
}
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我的输出是:
1 2 3 4 5
1 2 3 4 5
1 2 3 4 5
1 2 3 4 5
1 2 3 4 …Run Code Online (Sandbox Code Playgroud)