小编Har*_*man的帖子

我想删除Ruby,所以我试试这个.我该如何删除？

sudo apt-get autoremove ruby
Reading package lists... Done
Building dependency tree       
Reading state information... Done
Package 'ruby' is not installed, so not removed
0 upgraded, 0 newly installed, 0 to remove and 534 not upgraded.

here@jaskaran:/$ whereis ruby
    ruby: /usr/bin/ruby /usr/lib/ruby /usr/bin/X11/ruby /usr/share/man/man1/ruby.1.gz
here@jaskaran:/$ ruby -v
ruby 1.9.3p194 (2012-04-20 revision 35410) [i686-linux]

在登录模型中，我与图片表有实现关系

function picture () {
   return $this->hasOne('App\Picture');
}

现在我想要 Picture.picture_status = 1 和 User.user_status = 1 的数据

Login::with('picture')->where('picture_status', 1)->where('user_status',1);

但是如果条件不适用于图片表，我如何在两个表上实施和条件

我有问题表,存储了这么多问题.与question_topics相关的问题因此创建与问题有很多关系.现在它看起来像这样:

$this->Question->bindModel(
        array(
            'hasMany' => array(
                'QuestionTopic'=>array(
                    'className' => 'QuestionTopic',
                    'foreignKey' => 'question_id',
                    'dependent' => true,
                    'conditions' => array('QuestionTopic.areas_id' => 165),
                    'type' => 'left'
                )
            )
        )
);
print_r($this->Question->find('all')); 
die;

当我看到结果时,它看起来像这样

Array
(
    [0] => Array
        (
            [Question] => Array
                (
                    [id] => 89
                    [user_id] => 1
                    [question_group_id] => 0
                    [question] => jQuery function here
                    [target_id] => 1
                    [type] => 1
                    [order] => 1
                    [description] => additional info here 
                    [privacy_friend_id] => 
                    [channel_id] => 1
                    [status] => 0
                    [location] => Chandigarh, …

我有一个字段country_id和country_name,我想在Django rest Framework中更改这两个字段的名称

现在写我正在收到这些数据

{
  "data": [
    {
      "country_id": 1,
      "country_name": "Afghanistan"
    },
    {
      "country_id": 2,
      "country_name": "Aland Islands"
    } 
  ]
}

我在serializers.py文件中有变化,但对我不起作用

serializers.py

class CountrySerializer(serializers.ModelSerializer):
    name = serializers.SerializerMethodField('country_name')
    class Meta:
        model = Country
        fields = ('country_id', 'name')

在模型中

class Country(models.Model):
    country_id = models.AutoField(primary_key = True)
    country_name = models.CharField(max_length = 128)

    class Meta:
        db_table = 'countries'

我想要这些数据

 {
      "data": [
        {
          "id": 1,
          "name": "Afghanistan"
        },
        {
          "id": 2,
          "name": "Aland Islands"
        }
      ]
    }

得到此错误:/ v1/location/countries /上的AttributeError'CountrySerializer'对象没有属性'country_name'

我有查询相关的jquery.我的设计师用户制服,我想在运行时使用帮助jquery将其从一个元素中删除.制服:http://uniformjs.com/ 喜欢

<input type="checkbox" class="abc">

我知道如何申请但不知道如何删除

申请:

jQuery(".interactionClassNow").uniform();

去掉 ？

我已经浏览了laravel文档,我没有得到With或Load in queries 之间的不同,在哪种情况下我们需要使用With或Load？请描述一下

Model::find(1)->with('firstModel','SecondModel');

Model::find(1)->load('firstModel','SecondModel');

我正在学习有关学习WebRTC的书，并创建了一个演示4章。我在控制台中出现错误：

ReferenceError: webkitRTCPeerConnection is not defined

并且不明白我可以配置“ iceServers”：

这是我的JavaScript代码

function hasUserMedia(){
    navigator.getUserMedia = navigator.getUserMedia || navigator.webkitGetUserMedia || navigator.mozGetUserMedia || navigator.msGetUserMedia;
    return !!navigator.getUserMedia; 
}

function hasRTCPeerConnection() {
    window.RTCPeerConnection = window.RTCPeerConnection || window.webkitRTCPeerConnection || window.mozRTCPeerConnection;
    return !!window.RTCPeerConnection;
}


//This function will create our RTCPeerConnection objects, set up the SDP offer and response, and find the ICE candidates for both peers. page 48

function startPeerConnection(stream) {
    var configuration = {
        // Uncomment this code to add custom iceServers
        "iceServers": [{ "url": "stun:stun.1.google.com:19302" }] …

我想在ubuntu中安装RVM,我正在完成这些步骤

root@jaskaran-Vostro-1550:/home/user_name# sudo apt-get install curl

成功完成了这个

root@jaskaran-Vostro-1550:/home/user_name# curl -L https://get.rvm.io | bash -s stable

成功完成了这个

但是当我运行这个命令

root@jaskaran-Vostro-1550:/home/user_name# source ~/.rvm/scripts/rvm

这样的结果

bash: /root/.rvm/scripts/rvm: No such file or directory

这有什么不妥

首先我运行了这个命令

rails generate model FeedbackComment type:smallint reply:text

然后

rake db:migrate 

我收到了这个错误

StandardError: An error has occurred, this and all later migrations canceled:

undefined method `smallint' for #<ActiveRecord::ConnectionAdapters::PostgreSQLAdapter::TableDefinition:0x9d1a318>/var/www/blog/db/migrate/20140712064127_create_feedback_comments.rb:4:in `block in change'

如何在postgreSQL中通过命令创建smallint？

请帮帮我

我是python的初学者.我想在控制台中运行这个程序员,但它告诉我错误是什么错误.

>>> def fib(n):
...     a, b = 0, 1
...     while a < n:
...             print (a, end=' ')
  File "<stdin>", line 4
    print (a, end=' ')
                  ^
SyntaxError: invalid syntax

我的实际程序,我想运行:

>>> def fib(n):
...     a, b = 0, 1
...     while a < n:
...         print(a, end=' ')
...         a, b = b, a+b
...     print()
>>> fib(1000)