初始化对抽象类型的引用时,构造函数初始化列表中的{}初始化如何与()初始化不同?以下课程栏:
class AbstractBase
{
public:
AbstractBase() {}
virtual ~AbstractBase() = default;
virtual void ab() = 0;
};
class Foo : public AbstractBase
{
public:
Foo() {}
void ab() {}
};
class Bar
{
public:
Bar(const AbstractBase& base) : myBase{base} {}
private:
const AbstractBase& myBase;
};
int main()
{
Foo f{};
Bar b{f};
}
Run Code Online (Sandbox Code Playgroud)
编译时,我收到错误
test5.cpp: In constructor ‘Bar::Bar(const AbstractBase&)’:
test5.cpp:22:48: error: cannot allocate an object of abstract type ‘AbstractBase’
Bar(const AbstractBase& base) : myBase{base}
^
test5.cpp:2:7: note: because the following …Run Code Online (Sandbox Code Playgroud)