小编han*_*esr的帖子

Swift块不工作

我一直试图弄清楚如何在swift中使用JavaScriptCore.我遇到了问题但是当我必须处理块作为参数时,似乎立即运行块并且参数获取块的返回值.我究竟做错了什么?

工作目标C代码:

JSContext* context = [[JSContext alloc] initWithVirtualMachine:[[JSVirtualMachine alloc] init]];
context[@"test"] = ^(NSString *string) {
    //code
};
Run Code Online (Sandbox Code Playgroud)

我尝试过的:

1:

var ctx = JSContext(virtualMachine:JSVirtualMachine())
var ctx["test"] = {(string:NSString)->() in /*code*/ }

//Gives me "'JSContext' does not have a member named 'subscript'"
Run Code Online (Sandbox Code Playgroud)

2:

var ctx = JSContext(virtualMachine:JSVirtualMachine())
let n: (string: String)->() = {string in /*code*/}

ctx.setObject(n, forKeyedSubscript:"test")

//Gives me "Type '(x: String) -> () does not conform to protocol 'AnyObject'"
Run Code Online (Sandbox Code Playgroud)

3:

var ctx = JSContext(virtualMachine:JSVirtualMachine())
let n: (string: String)->() = {string in …
Run Code Online (Sandbox Code Playgroud)

block javascriptcore swift

7
推荐指数
1
解决办法
4114
查看次数

标签 统计

block ×1

javascriptcore ×1

swift ×1