Swift块不工作

Question

我一直试图弄清楚如何在swift中使用JavaScriptCore.我遇到了问题但是当我必须处理块作为参数时,似乎立即运行块并且参数获取块的返回值.我究竟做错了什么？

工作目标C代码:

JSContext* context = [[JSContext alloc] initWithVirtualMachine:[[JSVirtualMachine alloc] init]];
context[@"test"] = ^(NSString *string) {
    //code
};

我尝试过的:

1:

var ctx = JSContext(virtualMachine:JSVirtualMachine())
var ctx["test"] = {(string:NSString)->() in /*code*/ }

//Gives me "'JSContext' does not have a member named 'subscript'"

2:

var ctx = JSContext(virtualMachine:JSVirtualMachine())
let n: (string: String)->() = {string in /*code*/}

ctx.setObject(n, forKeyedSubscript:"test")

//Gives me "Type '(x: String) -> () does not conform to protocol 'AnyObject'"

3:

var ctx = JSContext(virtualMachine:JSVirtualMachine())
let n: (string: String)->() = {string in /*code*/}

ctx.setObject(n as AnyObject, forKeyedSubscript:"test")

//Gives me "Cannot downcast from '(string: String) -> () to non-@objc protocol type 'AnyObject'"

我在这里遗漏了什么,或者这只是Swift中的一个错误？

编辑:

我现在也尝试过Cast closures/blocks的建议

class Block<T> {
    let f : T
    init (_ f: T) { self.f = f }
}

然后

ctx.setObject(Block<()->Void> {
        /*code*/
    }, forKeyedSubscript: "test")

这个解决方案让我编译,但我收到运行时错误:

Thread 1: EXC_BREAKPOINT (code=EXC_I386_BPT, subcode=0x0)

Answer 1

它与Swift如何实现闭包有关.您需要使用@convention(block)来注释闭包是ObjC块.使用unsafeBitCast强制投它

var block : @convention(block) (NSString!) -> Void = {
   (string : NSString!) -> Void in 
    println("test")
}

ctx.setObject(unsafeBitCast(block, AnyObject.self), forKeyedSubscript: "test")

来自REPL

swift
Welcome to Swift!  Type :help for assistance.
  1> import Foundation
  2> var block : @convention(block)(NSString!) -> Void = {(string : NSString!) -> Void in println("test")}
block: @convention(block)(NSString!) -> Void =
  3> var obj: AnyObject = reinterpretCast(block) as AnyObject
obj: __NSMallocBlock__ = {} // familiar block type