我知道mysql中的boolean为tinyint (1).
今天我看到一个定义了整数的表tinyint(2),还有其他像int(4),int(6)...
大小在整数和tinyint类型的字段中意味着什么?
我有一个用于laravel安装的composer文件,其中包含以下composer.json文件:
{
"name": "laravel/laravel",
"description": "The Laravel Framework.",
"keywords": ["framework", "laravel"],
"license": "MIT",
"require": {
"laravel/framework": "4.1.*"
},
"autoload": {
"classmap": [
"app/commands",
"app/controllers",
"app/models",
"app/database/migrations",
"app/database/seeds",
"app/tests/TestCase.php"
]
},
"scripts": {
"post-install-cmd": [
"php artisan clear-compiled",
"php artisan optimize"
],
"post-update-cmd": [
"php artisan clear-compiled",
"php artisan optimize"
],
"post-create-project-cmd": [
"php artisan key:generate"
]
},
"config": {
"preferred-install": "dist"
},
"minimum-stability": "stable"
}
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我正在尝试添加哨兵包.在哨兵的网站上,它说我可以通过在composer.json文件中添加以下内容来安装它:
{
"require": {
"cartalyst/sentry": "2.0.*"
},
"minimum-stability": "dev"
}
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我尝试在当前laravel的末尾添加新的json对象,如下所示:
...
},
{
"require": …Run Code Online (Sandbox Code Playgroud) 我在代码中发现了一个关于类常量的怪异问题。虽然代码似乎可以正常运行,但我无法弄清PHP的原因注意:
Use of undefined constant PAYMENT_ERROR - assumed 'PAYMENT_ERROR' in /src/Micro/Payments/Manager.php on line 146
Manager.php函数中的代码如下所示:
$code = Result::PAYMENT_ERROR;
return new Result($code, $errMsg); // <- line 146 - causes PHP Notice
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对我来说奇怪的是,$code变量设置正确且不会触发任何通知。仅实例化Result确实如此。
Result类非常简单:
class Result
{
// ... boilerplate code skipped ...
// constant is defined like this:
const PAYMENT_ERROR = 2;
public function __construct($code, array $messages)
{
$this->code = $code;
$this->messages = $messages;
}
// ... other functions skipped as they are not relevat ...
}
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我将Result的常量传递给它自己的构造函数是否有问题?
我想保护我的/ tmp目录以防止内部文件被删除,但是"chmod + t/tmp"没有设置粘滞位.在mac os x上有替代方法吗?
我正在努力在vim中绑定Shift + - 组合.我已尝试下面的两个选项,没有可用的谷歌搜索没有带来任何相关信息.
nnoremap <S-\-> <C-W>-
nnoremap <S--> <C-W>-
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我正在运行Linux并希望绑定-密钥0和=密钥.
php ×2
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