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Jenkins返回状态码128

我正在尝试使用BitBucket GIT存储库设置Jenkins,但Jenkins控制台总是给我这个错误代码:

Started by user Dakado
Building in workspace /var/lib/jenkins/workspace/TEST852
Fetching changes from the remote Git repository
Fetching upstream changes from git://bitbucket.org/GameTeamCZ/gtplaytime.git
FATAL: Failed to fetch from git://bitbucket.org/GameTeamCZ/gtplaytime.git
hudson.plugins.git.GitException: Failed to fetch from git://bitbucket.org/GameTeamCZ/    gtplaytime.git
at hudson.plugins.git.GitSCM.fetchFrom(GitSCM.java:625)
at hudson.plugins.git.GitSCM.retrieveChanges(GitSCM.java:847)
at hudson.plugins.git.GitSCM.checkout(GitSCM.java:872)
at hudson.model.AbstractProject.checkout(AbstractProject.java:1411)
at hudson.model.AbstractBuild$AbstractBuildExecution.defaultCheckout(AbstractBuild.java:651)
at jenkins.scm.SCMCheckoutStrategy.checkout(SCMCheckoutStrategy.java:88)
at hudson.model.AbstractBuild$AbstractBuildExecution.run(AbstractBuild.java:560)
at hudson.model.Run.execute(Run.java:1670)
at hudson.model.FreeStyleBuild.run(FreeStyleBuild.java:46)
at hudson.model.ResourceController.execute(ResourceController.java:88)
at hudson.model.Executor.run(Executor.java:231)
Caused by: hudson.plugins.git.GitException: Command "git fetch --tags --progress git://    bitbucket.org/GameTeamCZ/gtplaytime.git +refs/heads/*:refs/remotes/origin/*"     returned status code 128:
stdout: 
stderr: bitbucket.org[0: 131.103.20.167]: errno=Connection timed out
bitbucket.org[0: …
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status bitbucket bit jenkins

9
推荐指数
1
解决办法
2万
查看次数

如何在多个分隔符上分隔String?

我有字符串"1000:2000,3000",我需要将它分成3个字符串,所以像这样:

"1000"
"2000"  
"3000"
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我的代码看起来像:

int datas = 0;
String item = "";
String data = "";
String pocet = "";
List<String> items = "1000:2000,3000";
for (int ii = 0; ii < items.size(); ii++) {
    System.out.println(items.get(ii));
    int delkaid = items.get(ii).indexOf(":");
    int delkadat = items.get(ii).indexOf(",") - items.get(ii).indexOf(":");
    int delkapoctu = items.get(ii).length() - items.get(ii).indexOf(",");


    for (int ite = 0; ite < delkaid; i++) {
        item = item + items.get(ii).charAt(ite) + "";
    }

    for (int ite = 0; ite < delkadat; …
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java string divide

0
推荐指数
1
解决办法
83
查看次数

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