小编Spl*_*luf的帖子

ng-selected为true但未选择

所以,我有一个选择列表,我试图动态选择项目.问题是,即使doe表达式被评估为"true",该选项仍未被选中

<label for="articlePage">Page:</label>
<select class="form-control pageList" name="articlePage" required="" ng-model="article.page_ID">
    <option ng-repeat="page in pages" ng-selected ="{{page.id == article.page_ID}}" value={{page.id}}>{{page.name}}</option>
</select><br>
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范围(页数):

$scope.pages = [
        { name: "Home",                 id: "1" },
        { name: "Plugs",                id: "2" },
        { name: "Pack Bedding",         id: "3" },
        { name: "Pot Bedding",          id: "4" },
        { name: "Poinsettias",          id: "5" },
        { name: "Sales",                id: "6" },
        { name: "Process Quality",      id: "7" },
        { name: "Environment",          id: "8" },
        { name: "Process Technology",   id: "9" …
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angularjs

7
推荐指数
1
解决办法
6989
查看次数

在ajax响应之后执行soundmanager2

我试图在ajax响应中执行脚本,似乎无法找到任何方法.我的脚本加载在html-head标签中,我也有一个id为id ="browsemusic"的div,我的ajax响应在那里.

我的php文件生成页面:

include('dbcon.php');
if(isset($_REQUEST['all']) && $_REQUEST['all'] != ''){
    //===============================Button "ALL"====================================
    unset($_REQUEST['kw']);
    unset($_REQUEST['genre']);
    $query = "select * from music";
    $result = mysqli_query($link, $query) or die (mysqli_error());
    echo '<ul id="sortable1" class="connected">';
    while($info = mysqli_fetch_array( $result )){
        echo '<li><div class="ui360"><button type="button" class="addtoplaylist" >Add</button><a href="' . $info['path'] . '"> '.$info['artist'].' - '.$info['title'].' ('.$info['album'].') '.'</a></div><hr /></li>';
    };
    echo '</ul>';
}elseif (isset($_REQUEST['kw']) && $_REQUEST['kw'] != ''){
    //============================= Search for music ================================
    $kws = $_REQUEST['kw'];
    $kws = mysqli_real_escape_string($link, $kws);

    $query = "select * from music where …
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javascript php ajax soundmanager2

0
推荐指数
1
解决办法
913
查看次数

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soundmanager2 ×1