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R错误:"要替换的项目数不是替换长度的倍数"

我对R很新.当值设置得较低时,我的脚本工作正常.我需要计算概率并且需要至少1,000,000个样本.我的第一个循环返回此错误:

Error in new.matrix[i, ] <- as.vector(table(million.rep[, i])) : number of items to replace is not a multiple of replacement length
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我的剧本:

actual.prob <- c(.14, .14, .16, .13, .19, .24)
number.in.bag <- c(8,6,20,9,10,5)

million.rep <- replicate(1000000, sample(1:6, 58, replace= T, actual.prob))



new.matrix <- matrix(nrow= 1000000, ncol=6)
# Note to other readers... the above line throws the error.

for(i in 1:1000000){
new.matrix[i,] <- as.vector(table(million.rep [, i]))
}


y <- c()
for(i in 1:1000000){
y[i] <- sum(new.matrix[i,] == number.in.bag)
}
y
sum(y …
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r matrix

5
推荐指数
1
解决办法
3万
查看次数

Find the most repeated row in a matrix

I have about 10000 replicates of a sample in a matrix. My matrix has 1000 rows and 6 columns. Numbers in the columns range from 0:58 depending on the sample.

actual.prob <- c(.14, .14, .16, .13, .19, .24)
million.rep <- replicate(10000, sample(1:6, 58, replace= T, actual.prob))
new.matrix <- matrix(nrow= 10000, ncol=6)
for(i in 1:10000){
  new.matrix[i,] <- as.vector(table(factor(million.rep[,i], levels=1:6)))
}
new.matrix[1:10,]

          [,1] [,2] [,3] [,4] [,5] [,6]
     [1,]    3    7   11   11   11   15
     [2,]    7    6   12    5   19    9 …
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row r matrix duplicates

5
推荐指数
1
解决办法
187
查看次数

标签 统计

matrix ×2

r ×2

duplicates ×1

row ×1