小编Sal*_*ern的帖子

当我将ubuntu从15.10升级到16.04时,我在yii2项目中有这个错误

SQLSTATE[42000]: Syntax error or access violation: 1055 Expression #3
of SELECT list is not in GROUP BY clause and contains nonaggregated column 
'iicityYii.opportunity_conditions.money' which is not functionally dependent 
on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by

正在执行的SQL是:

SELECT SUM(oc.money),op.id,oc.money,
            op.mantaghe,
            op.`time`, op.`id`, `op`.`logo`,
           `pd`.`user_id`, `op`.`name`, 
           `pd`.`co_name`, `op`.`address`, 
           `op`.`project_type_id`, `op`.`state_id`
FROM `opportunity` op 
INNER JOIN `profile_details` pd  ON op.user_id=pd.user_id  
INNER JOIN `opportunity_conditions` oc ON   op.id=oc.opportunity_id
GROUP BY `op`.`id`
ORDER BY `op`.`id` DESC

怎么解决我的问题？

我用ubuntu 16.04.
PHP Version 7.0.4-7ubuntu2.
Apache/2.4.18 (Ubuntu).
PHP extension: mysqli(在phpmyadmin撰写).

我从我的ubuntu升级15.10 to 16.04,我有这个错误:

我的项目在我的服务器中正确运行,但我无法在我的操作系统中运行:

Database Exception – yii\db\Exception
SQLSTATE[HY000] [2002] No such file or directory
?
Caused by: PDOException
SQLSTATE[HY000] [2002] No such file or directory

in /var/www/html/iicitySite/vendor/yiisoft/yii2/db/Connection.php at line 579

我想在GridView :: widget中添加一列

 <?= GridView::widget([
        'dataProvider' => $dataProvider,
        'filterModel' => $searchModel,
        'columns' => [
            ['class' => 'yii\grid\SerialColumn'],

            'id',
            'owner_id',
            'situation',
            'address',
              [
//            'attribute' => 'address',
            'format' => 'html',
            'label' => 'Image',
            'value' => function ($data) {
                return Html::img('http://iicity.ir/' . $data['address'],
                    ['width' => '60px']);
            },
        ],

            'slideshow_text',

            ['class' => 'yii\grid\ActionColumn'],
        ],
    ]); ?>

我想添加'owner_id'的名称 ,从另一个表名称在(帐户)表表中:

id = 1 name = jack

id = 2 name = sara

我使用 Yii2 框架，这是我的行为函数 ShippingController

  public function behaviors()
        {
        return [
            'access' => [
                'class' => \yii\filters\AccessControl::className(),
                'rules' => [
                    // deny all POST requests
//                        [
//                        'actions' => ['index', 'create'],
//                        'allow' => TRUE,
//                    ],
                        [
                        'actions' => ['index', 'create', 'init'],
                        'allow' => true,
                        'roles' => ['?'],
                        'matchCallback' => function ($rule, $action)
                            {
                            return $action->controller->redirect('action');
                            }
                    ],
                    'denyCallback' => function ($rule, $action)
                        {
                        return $action->controller->redirect('not');
                        }
                // everything else is denied
                ],
            ],
        ];

        }

matchCallback 运行良好，但

在 …

我有一个链接(href)到另一个网站,但我有问题

这是我的代码:

          return Html::a('Create More', ["https://face.com/"], ['class' => 'btn btn-primary', 'role' => 'modal-remote']);

为什么我的链接是一个新动作？我想改变我的baseurl到https://face.com/但是dosnt工作

这是我的新链接:

https://niniplus.com/newadmin/index.php/https://face.com

我想从这个 url 字符串中找到变量：

这是我的字符串：

$var = "http://localhost/trans/site/index#ads=10"

我怎样才能$ads从这个字符串中得到？