小编nde*_*rge的帖子

有没有人知道使用Play框架和SLICK(ScalaQuery)的好教程或示例项目(github)？我正在努力让他们一起工作.

我收到此错误:

[info] play - Application started (Dev)
[error] application - 

! @6b13oi41c - Internal server error, for request [GET /listBooks] ->

play.core.ActionInvoker$$anonfun$receive$1$$anon$1: Execution exception [[NoClassDefFoundError: Could not initialize class scala.slick.ast.opt.Relational$]]
    at play.core.ActionInvoker$$anonfun$receive$1.apply(Invoker.scala:134) [play_2.9.1-2.0.2.jar:2.0.2]
    at play.core.ActionInvoker$$anonfun$receive$1.apply(Invoker.scala:115) [play_2.9.1-2.0.2.jar:2.0.2]
    at akka.actor.Actor$class.apply(Actor.scala:318) [akka-actor-2.0.2.jar:2.0.2]
    at play.core.ActionInvoker.apply(Invoker.scala:113) [play_2.9.1-2.0.2.jar:2.0.2]
    at akka.actor.ActorCell.invoke(ActorCell.scala:626) [akka-actor-2.0.2.jar:2.0.2]
    at akka.dispatch.Mailbox.processMailbox(Mailbox.scala:197) [akka-actor-2.0.2.jar:2.0.2]
Caused by: java.lang.NoClassDefFoundError: Could not initialize class scala.slick.ast.opt.Relational$
    at scala.slick.driver.BasicProfile$class.processAST(BasicProfile.scala:18) ~[slick_2.10.0-M4-0.10.0-M2.jar:0.10.0-M2]
    at scala.slick.driver.PostgresDriver$.processAST(PostgresDriver.scala:69) ~[slick_2.10.0-M4-0.10.0-M2.jar:0.10.0-M2]
    at scala.slick.driver.BasicProfile$class.createQueryBuilder(BasicProfile.scala:22) ~[slick_2.10.0-M4-0.10.0-M2.jar:0.10.0-M2]
    at scala.slick.driver.PostgresDriver$.createQueryBuilder(PostgresDriver.scala:69) ~[slick_2.10.0-M4-0.10.0-M2.jar:0.10.0-M2]
    at scala.slick.driver.BasicProfile$class.buildSelectStatement(BasicProfile.scala:23) ~[slick_2.10.0-M4-0.10.0-M2.jar:0.10.0-M2]
    at scala.slick.driver.PostgresDriver$.buildSelectStatement(PostgresDriver.scala:69) ~[slick_2.10.0-M4-0.10.0-M2.jar:0.10.0-M2]
[error] application - 

这是我的书模型:

package …

我遇到了我的Spring控制器问题 - 我没有找到默认的构造函数 - 但是他们确实有一个我试图通过applicationContext.xml创建的构造函数 - 以下是相关的一点:

<bean id="PcrfSimulator" class="com.rory.services.pcrf.simulator.PcrfSimulator" init-method="start">  
</bean>

<bean id="CacheHandler" class="com.rory.services.pcrf.simulator.handlers.CacheHandler">
    <constructor-arg index="0" type="com.rory.services.pcrf.simulator.CustomGxSessionIdCacheImpl">
        <bean factory-bean="PcrfSimulator" factory-method="getGxSessionIdCache">
        </bean>
    </constructor-arg>       
</bean>

IE浏览器.我首先创建一个bean,然后尝试将该bean的方法调用结果传递给第二个bean的(CacheHandler)构造函数.

这是CacheHandler的开始:

    @Controller
    public class CacheHandler {

    private final CustomGxSessionIdCacheImpl gxSessionIdCache;

    public CacheHandler(CustomGxSessionIdCacheImpl gxSessionIdCache) {
        this.gxSessionIdCache = gxSessionIdCache;
    }

这是我得到的错误:

org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'cacheHandler' defined in URL [jar:file:/users/rtorney/Documents/apache-tomcat-7.0.25/webapps/PCRFSimulator-4.0/WEB-INF/lib/PCRFSimulator-4.0.jar!/com/rory/services/pcrf/simulator/handlers/CacheHandler.class]: Instantiation of bean failed; nested exception is org.springframework.beans.BeanInstantiationException: Could not instantiate bean class [com.rory.services.pcrf.simulator.handlers.CacheHandler]: No default constructor found; nested exception is java.lang.NoSuchMethodException: com.rory.services.pcrf.simulator.handlers.CacheHandler.<init>()

任何帮助深表感谢!

我正在尝试使用sbt-web和sbt-js-engine特别是用npm而不是webjars来解析我的依赖关系.

我的问题是target/web/public/main/lib在web-stage任务期间不会将依赖项复制到文件夹中,因为使用webjar就是这种情况.

我使用sbt-js-engine的示例项目进行测试.有了这个项目,我希望console-browserify从package.json文件target/web/public/main/lib夹中的文件中找到依赖项,但事实并非如此.

也许我完全误解了什么？

我知道一个方法可以有这样的代码:

def m(p1:Int => Int) ...

这意味着此方法采用返回Int的函数p1

但是在浏览Play的同时!框架代码我找到了一个具有难以理解的方法的特征:

trait Secured {

  def username(request: RequestHeader) = request.session.get(Security.username)

  def onUnauthorized(request: RequestHeader) = Results.Redirect(routes.Auth.login)

  def withAuth(f: => String => Request[AnyContent] => Result) = {
    Security.Authenticated(username, onUnauthorized) { user =>
      Action(request => f(user)(request))
    }
  }

  /**
   * This method shows how you could wrap the withAuth method to also fetch your user
   * You will need to implement UserDAO.findOneByUsername
   */
  def withUser(f: User => Request[AnyContent] => Result) = withAuth { username => implicit request …

我已经开始使用Play和Play-ReactiveMongo插件,并在GET"document by id"场景中测试404响应.不幸的是,而不是Play返回404 NotFound响应,我得到了这个异常:

java.util.NoSuchElementException: JsError.get
        at play.api.libs.json.JsError.get(JsResult.scala:11) ~[play_2.10.jar:2.1.1]
        at play.api.libs.json.JsError.get(JsResult.scala:10) ~[play_2.10.jar:2.1.1]
        at play.modules.reactivemongo.json.collection.JSONGenericHandlers$StructureBufferWriter$.write(jsoncollection.scala:44) ~[play2-reactivemongo_2.10-0.9.jar:0.9]
        at play.modules.reactivemongo.json.collection.JSONGenericHandlers$StructureBufferWriter$.write(jsoncollection.scala:42) ~[play2-reactivemongo_2.10-0.9.jar:0.9]
        at reactivemongo.api.collections.GenericQueryBuilder$class.reactivemongo$api$collections$GenericQueryBuilder$$write(genericcollection.scala:323) ~[reactivemongo_2.10-0.9.jar:0.9]
        at reactivemongo.api.collections.GenericQueryBuilder$class.cursor(genericcollection.scala:333) ~[reactivemongo_2.10-0.9.jar:0.9]

如果id参数与现有文档匹配,则下面的getById函数成功返回单个文档,如果找不到文档,则在"one [JsValue]"行上成功返回异常.

路线文件:

GET       /items/:id            controllers.ItemsController.getById(id: String)

控制器对象:

object ItemsController extends Controller with MongoController {

    def itemsCollection: JSONCollection = db.collection[JSONCollection]("items")

    def getById(id: String) = Action {
       Async {  

              val query = Json.obj("_id" -> Json.obj("$oid" ->id))
              val futureItem = itemsCollection.
                find(query).
                one[JsValue]

              futureItem.map {
                case Some(item) => Ok(item)
                case None => NotFound(Json.obj("message" -> …

根据这些 文章,Websocket的成功率仅为63%(如果你有一个支持websocket的浏览器).

这篇InfoQ文章(http://www.infoq.com/articles/Web-Sockets-Proxy-Servers)表示,您有更好的机会使用安全Websockets(wss://)进行连接.

有没有人对企业就绪应用程序使用Websockets,企业代理和防火墙背后有任何反馈？

如果我的问题不在话题,我很抱歉.

此致,尼科

免责声明:我对Gradle很新.

我正在尝试使用Gradle(1.0-rc1)构建我的项目,使用来自Maven artefact的Snapshot依赖项.

但是当我尝试使用解决依赖关系时gradle --info dependencies,我收到以下错误:

FAILURE: Build failed with an exception.

* What went wrong:
Execution failed for task ':dependencies'.
> Could not resolve all dependencies for configuration ':compile'.
   > Could not resolve group:com.l2fprod, module:l2fprod-common-all, version:7.3.
     Required by:
         :test:unspecified > org.valkyriercp:valkyrie-rcp-core:1.1-SNAPSHOT
      > Could not HEAD 'https://raw.github.com/Ekito/maven-repo/master/ \
        snapshots/com/l2fprod/l2fprod-common-all/7.3/l2fprod-common-all-7.3.jar'.
   > Could not resolve group:org.valkyriercp, module:valkyrie-rcp-resources, 
     version:1.1-SNAPSHOT.
     Required by:
         :test:unspecified > org.valkyriercp:valkyrie-rcp-core:1.1-SNAPSHOT
      > Could not resolve group:org.valkyriercp, module:valkyrie-rcp, 
        version:1.1-SNAPSHOT.
         > Could not HEAD 'https://raw.github.com/Ekito/maven-repo/master/ \
           snapshots/org/valkyriercp/valkyrie-rcp/1.1-SNAPSHOT \
           /valkyrie-rcp-1.1-SNAPSHOT.jar'.

但Maven …

我试图通过cookie管理我的用户.这并不容易,因为绝对没有关于这个主题的文档.

在样本"zentask"的帮助下,我做了这个:

session("username", filledForm.field("username").value());

public class Secured{

    public static Session getSession() {
        return Context.current().session();
    }

    public static String getUsername() {
        return getSession().get("username");
    }

    public static boolean isAuthorized() throws Exception {
        String username = getUsername();
        if (username == null)
            return false;
        long userCount = DatabaseConnect.getInstance().getDatastore()
                .createQuery(User.class).field("username").equal(username)
                .countAll();

        if (userCount == 1)
            return true;

        return false;

    }

我这样使用它:

public static Result blank() throws Exception {

        if (Secured.isAuthorized())
            return ok(Secured.getUsername());
        else
            return ok(views.html.login.form.render(loginForm));

    }

现在我有几个问题/问题:

• 1.)Cookie不是dectypted,看起来总是一样.例如bdb7f592f9d54837995f816498c0474031d44c1a-username%3Akantaki

• 2.)Security.Authenticator类有什么作用？

• 3.)我认为通过cookie进行用户管理是一个非常普遍的问题,确实可以玩!2.0为我提供了完整的解决方案吗？或者至少有一些文件？

我正在尝试将库从 Scala 2.13 迁移到 Scala 3，但现有代码无法编译。

这是一个片段

trait Identity
trait Authenticator

trait Env {
  type I <: Identity
  type A <: Authenticator
}

trait IdentityService[T <: Identity]
trait AuthenticatorService[T <: Authenticator]

trait Environment[E <: Env] {
  def identityService[T <: Identity]: IdentityService[E#I]
  def authenticatorService: AuthenticatorService[E#A]
}

Scala 3 编译器失败并显示：

error] 14 |  def identityService[T <: Identity]: IdentityService[E#I]
[error]    |                                                      ^
[error]    |                                         E is not a legal path
[error]    |                                         since it is not a concrete type
[error] -- Error: 
[error] …

我create在Play中有一个动作!框架控制器,应返回HTTP状态代码Created并将客户端重定向到创建的对象的位置.

public class SomeController extends Controller {

    public static void create() {
        Something something = new Something();
        something.save();
        response.status = StatusCode.CREATED;  // Doesn't work!
        show(something.id);
    }

    public static void show(long id) {
        render(Something.findById(id));
    }
}

另请参阅Play中的方法链接!框架文档.

上面的代码返回状态代码302 Found而不是201 Created.我该怎么做让Play返回正确的状态(和Location标题)？