小编Leo*_*mel的帖子

ORA-24374:在获取或执行并获取之前定义未完成

这种 if 语句有效吗?

if($result1 = oci_fetch_array($oms_query2) != null){}
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它返回错误:

警告:oci_fetch_array() [function.oci-fetch-array]:ORA-24374:在获取或执行和获取之前定义未完成

这是代码片段:

$oms_query = oci_parse($conn_oms,"select * from R_VALIDATION order by query_id");
oci_execute($oms_query);            
while($row = oci_fetch_assoc($oms_query)) {
    extract($row);
    If ($ACTIVE=='Y') {
        $TOTAL++;
        $result = array();      
        $FIELD=explode(';',$FIELDS);
        $FIELD_COUNT=count($FIELD);
        $_SESSION[ 'field' ] = $FIELD;
        $_SESSION[ 'field_count' ] = $FIELD_COUNT;
        $testing = 0;
        $oms_query2 = oci_parse($conn_oms,$QUERY);
        oci_execute($oms_query2);   
        if($result1 = oci_fetch_array($oms_query2) != null) {
            var_dump($result1);
            $IMPACTED++;
            if($FIELD[0]!=null) {
                $oms_query3 = oci_parse($conn_oms,$QUERY);
                oci_execute($oms_query3); 
                while($result = oci_fetch_array($oms_query3))
                    $testing++;

                echo'<tr><td height="100%" bgcolor = "Linen" align="center" valign="middle"><b>'.$QUERY_ID.'</b></td><td bgcolor = …
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php oracle10g

5
推荐指数
1
解决办法
6062
查看次数

致命错误:非抽象方法News_model :: __ construct()必须包含body [CodeIgniter]

我正在尝试CodeIgniter用户指南版本2.2.0中的教程.我只是按照粘贴的代码,但我收到此错误消息.这里到底有什么不对?

Fatal error: Non-abstract method News_model::__construct() must contain 
body in /var/www/leomel/application/models/news_model.php on line 3
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源代码:

<?php
class News extends CI_Controller {
   public function __construct()
   {
     parent::__construct();
     $this->load->model('news_model');
   }

   public function index()
   {
     $data['news'] = $this->news_model->get_news();
     $data['title'] = 'News archive';

     $this->load->view('templates/header', $data);
     $this->load->view('news/index', $data);
     $this->load->view('templates/footer');
   }

   public function view($slug)
   {
     $data['news'] = $this->news_model->get_news($slug);
     if (empty($data['news_item']))
     {
        show_404();
     }

     $data['title'] = $data['news_item']['title'];

     $this->load->view('templates/header', $data);
     $this->load->view('news/view', $data);
     $this->load->view('templates/footer');
   }
}
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php codeigniter

0
推荐指数
1
解决办法
1万
查看次数

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