所以我的目标是让几个容器使用rabbitmq 消息相互交互(rabbitmq 服务器在一个单独的容器中)
兔子.py
class Rabbit:
host = 'rabbitmq-host'
userid = 'test'
password = 'test'
class Consumer(Rabbit):
def __init__(self, exchange_name):
self.exchange_name = exchange_name
self.connection = None
try:
credentials = pika.PlainCredentials(self.userid, self.password)
params = pika.ConnectionParameters(self.host, 5672, '/', credentials)
self.connection = pika.BlockingConnection(params)
except Exception as ex:
print(ex)
if self.connection is not None and self.connection.is_open:
self.connection.close()
raise ex
self.channel = self.connection.channel()
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凭证测试:测试存在,我重新检查。
然后从另一个文件(main.py)创建消费者
c = Consumer('media')
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docker-compose.yml
version: '3'
services:
rabbitmq-server:
image: "rabbitmq:3-management"
hostname: "rabbitmq-host"
environment:
RABBITMQ_ERLANG_COOKIE: "SWQOKODSQALRPCLNMEQG"
RABBITMQ_DEFAULT_USER: "test"
RABBITMQ_DEFAULT_PASS: "test"
RABBITMQ_DEFAULT_VHOST: …Run Code Online (Sandbox Code Playgroud) 所以我使用DataContext作为与DB的连接.我想从DB中获取所有公司,但删除的公司除外.我的公司对象:
[Table(Name = "Companies")]
class Company {
[Column(IsPrimaryKey = true, IsDbGenerated = true)]
public int Id { get; set; }
[Column]
public bool Deleted { get; set; }
[Column]
public DateTime DateCreated { get; set; }
[Column]
public DateTime? DateModified { get; set; }
[Column]
public string Name { get; set; }
private EntitySet<Platform> _Platforms;
[Association(Storage = "_Platforms", OtherKey = "CompanyId")]
public virtual EntitySet<Platform> Platforms {
get {
return this._Platforms;
}
set {
this._Platforms.Assign(value);
}
}
public Company() {
this._Platforms …Run Code Online (Sandbox Code Playgroud)