小编Ale*_*io1的帖子

如何在Struts2中使用if有两个条件

我遍历一个项目列表,如果元素的状态等于学生或教师,则需要显示特定的下拉列表.以下代码显示所有字段,但不显示任何元素的下拉列表!

 <s:iterator value="listOfPeople" status="element">
   .....
  <s:if test='%{elements[#element.index].Status.equalsIgnoreCase("Student") ||
          elements[#element.index].Status.equalsIgnoreCase("Teacher")}'>

            <s:select name="elements[%{#element.index}].Status"
                               id="elements[%{#element.index}].Status"
                               label="Status"
                               list="#{'Student':'Student','Teacher':'Teacher'}"
                               headerKey = "-1"
                               headerValue=" "
                               value="%{Status}"
             />

    </s:if>
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在控制器中:

    PeopleModel peopleModel = new PeopleModel();
    listOfPeople = peopleModel.findPeople();
    System.out.println("size is:" + listOfPeople.size());  //returns 8
    return "listPeople";
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我的型号:

    List<People> people = new ArrayList();
    final Session session = HibernateUtil.getSession();
    try {
        final Transaction tx = session.beginTransaction();
        try {

            Criteria criteria = session.createCriteria(People.class, "People")
            people.addAll((List<People>) criteria.list());
            if (!tx.wasCommitted()) {
                tx.commit();
            }
            if (session.isOpen()) {
                session.close();
            }
            System.out.println("size is ::: " …
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jsp struts2

5
推荐指数
1
解决办法
2万
查看次数

如何从Hibernate 4.3.4.Final中检索sessionFactory?

以前我使用以下代码来配置sessionFactory,但是在将我的hibernate版本从4.2.1.Final升级到4.3.4.Final后,我无法使用以下代码检索sessionFactory,因为不推荐使用ServiceRegistryBuilder().

我使用此链接创建它,但提供的函数没有返回任何东西,因此它遇到预编译错误.

 private static SessionFactory configureSessionFactory() {
        try {
            Configuration configuration = new Configuration();
            configuration.configure();
            serviceRegistry = new ServiceRegistryBuilder().applySettings(configuration.getProperties()).buildServiceRegistry();
            sessionFactory = configuration.buildSessionFactory(serviceRegistry);
            return sessionFactory;
        } catch (HibernateException e) {
            System.out.append("** Exception in SessionFactory **");
            e.printStackTrace();
        }
        return sessionFactory;
    }

     static {
    try {
        sessionFactory = configureSessionFactory();
    } catch (Exception e) {
        System.err.println("%%%% Error Creating SessionFactory %%%%");
        e.printStackTrace();
    }
}

private HibernateUtil() {
}

public static SessionFactory getSessionFactory() {
    return sessionFactory;
}

public static Session getSession() throws HibernateException { …
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java hibernate sessionfactory

4
推荐指数
1
解决办法
1万
查看次数

为什么我收到JDBC驱动程序警告和ThreadLocal错误?

我在GlassFish上运行我的应用程序,我使用Spring Security和Hibernate.当我运行应用程序时,GlassFish控制台上将显示以下警告和错误.我该如何避免它们?

WARNING:   The web application [] registered the JDBC driver [com.mysql.jdbc.Driver] but failed to unregister it when the web application was stopped. To prevent a memory leak, the JDBC Driver has been forcibly unregistered.
SEVERE:   The web application [] created a ThreadLocal with key of type [java.lang.ThreadLocal] (value [java.lang.ThreadLocal@1087985b]) and a value of type [org.hibernate.internal.SessionImpl] (value [SessionImpl(PersistenceContext[entityKeys=[],collectionKeys=[]];ActionQueue[insertions=[] updates=[] deletions=[] collectionCreations=[] collectionRemovals=[] collectionUpdates=[] unresolvedInsertDependencies=UnresolvedEntityInsertActions[]])]) but failed to remove it when the web application was stopped. Threads are going to be …
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java hibernate struts2 spring-security glassfish-4

3
推荐指数
1
解决办法
4545
查看次数

我应该使用会话来实现搜索框吗?

我有一个包含以下字段的搜索表单

price, status, owner
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当用户填写所有字段时,请求将被发送到后端以显示具有指定价​​格,状态和所有者的产品的类别列表.用户可以单击每个类别以查看其产品列表.

为了实现它,我有以下方法来检索类别,并将搜索字段(价格,状态,所有者)放入会话中以在搜索的下一页中可用(当选择类别时).

参数的值可能太长了,我更喜欢将它们作为GET来轻松地为结果添加书签.

public String retrieveCategories(){
        //... here I retrieve categories which their products are matched 
        //with the search fields
        Map session = ActionContext.getContext().getSession();
        session.put("Items", this.items);
        return "SUCCESS";
   }
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显示所有类别后,用户可以单击每个类别以查看其产品.类别的名称将发送到后端,因此我将从会话中检索值以搜索具有所选类别的相同规格的产品.

public String retrieveProductsOfSelectedCategory(){
        Map session = ActionContext.getContext().getSession();
        this.items = (Items) session.get("Items");
        //... here I retrieve products of the selected category based on values retrieved
       // from session
   }
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我想知道如果不是你的建议,实施它是否是一个好习惯?

java session struts2

0
推荐指数
1
解决办法
188
查看次数