我有这个循环,我将如何结束循环?
void loop() {
// read the pushbutton input pin:
a ++;
Serial.println(a);
analogWrite(speakerOut, NULL);
if(a > 50 && a < 300){
analogWrite(speakerOut, 200);
}
if(a <= 49){
analogWrite(speakerOut, NULL);
}
if(a >= 300 && a <= 2499){
analogWrite(speakerOut, NULL);
}
Run Code Online (Sandbox Code Playgroud) 关于如何将代码中的"可食用"转换为会话以在不同页面上显示为标签的任何想法.将非常感谢帮助.
标签将显示消息,如是可以吃
代码吼叫
public int totalCalories()
{
return grams * calsPerGram;
}
public string getFruitInfo()
{
string s;
if (edible == true)
{
s = fName + " is good and it has " + totalCalories() +
"calories";
}
else
{
s = "Hands off! Not edible";
//edible = Sesion ["ediblesesion"] as bool;
// Session ["ediblesession"] = edible;
}
return s;
}
}
Run Code Online (Sandbox Code Playgroud) 如果我有几个类在同一页面上使用相同的连接字符串,我应该保持连接open();并在完成后关闭它或保持打开和关闭.
以下示例
protected void Page_Load(object sender, EventArgs e)
{
cs.Open();
something ...
cs.Close();
}
protected void Button1_Click(object sender, EventArgs e)
{
cs.Open();
something .....
cs.Close();
}
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或这个
protected void Page_Load(object sender, EventArgs e)
{
cs.Open();
something ...
}
protected void Button1_Click(object sender, EventArgs e)
{
something .....
cs.Close();
cs.Dispose();
}
Run Code Online (Sandbox Code Playgroud) 如何更改我的活动记录以显示我的日期为DD MM YYYY而不是YYYY MM DD?
当前显示
2016年1月7日
目标显示
2016年7月1日
当前 观点
<?php echo $row->start_date; ?>
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试图 查看
<?php echo $row->DATE_FORMAT(start_date, '%d/%m/%Y'); ?>
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模型
class Profiles_model extends CI_Model
{
function get_bank()
{
$this->db->where('mem_id', $this->session->userdata("id"));
$query = $this->db->get('bank');
return $query->result();
}
}
Run Code Online (Sandbox Code Playgroud) 大家好我有一个简单的插入语句,我知道有些东西丢失了,因为当我点击按钮插入不插入的数据.有任何想法吗?
protected void saveyear_Click(object sender, EventArgs e)
{
OleDbConnection connection = new OleDbConnection("Provider=Microsoft.Jet.OLEDB.4.0;Data Source=|DataDirectory|\\ASPNetDB.mdb;Persist Security Info=True");
OleDbDataAdapter da = new OleDbDataAdapter();
da.InsertCommand = new OleDbCommand("INSERT INTO DVD_Infomation (Year) VALUES (@Year)", connection);
{
da.InsertCommand.Parameters.AddWithValue("@Year", Year.Text);
}
connection.Open();
da.InsertCommand.ExecuteNonQuery();
connection.Close();
}
Run Code Online (Sandbox Code Playgroud) 我有用于构建自定义复选框的代码HTML。CSS我相信我的代码具有正确的网络工具包,但它似乎不适用于 FireFox。
这是代码:
超文本标记语言
<input type='checkbox' style="float: left" class='regular-checkbox big-checkbox'
checked='checked' id='product-45-45' name='product_id_page-0[45-45]'
value='45-45' data-first_price="11.99" data-second_price="" data-paysys="" />
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CSS
.regular-checkbox {
-webkit-appearance: none;
-moz-appearance: none;
background-color: #fafafa;
border: 1px solid #cacece;
box-shadow: 0 1px 2px rgba(0,0,0,0),inset 0 -15px 10px -12px rgba(0,0,0,0);
-moz-box-shadow: 0 1px 2px rgba(0,0,0,0),inset 0 -15px 10px -12px rgba(0,0,0,0);
-webkit-box-shadow: 0 1px 2px rgba(0,0,0,0),inset 0 -15px 10px -12px rgba(0,0,0,0);
padding: 9px;
border-radius: 20px;
-moz-border-radius: 20px;
-webkit-border-radius: 20px;
display: inline-block;
position: relative;
}
.regular-checkbox:active,
.regular-checkbox:checked:active …Run Code Online (Sandbox Code Playgroud) 我有一个 Angular 帖子到节点,根据响应代码我想执行不同的任务。
在我的节点中,我有 res.send 来根据操作节点端发回不同的响应代码。
我有一个小的 if else 语句,但它似乎只运行 200 响应代码,它不打印 400 或其他代码
我的代码
FirstModule.controller('LoginController', function($scope, $http) {
$scope.formData = {};
$scope.LoginForm = function() {
var data = {
LoginEmail: $scope.sometext.LoginEmail
};
$http({
url: 'http://localhost:8080/back-end/controller',
method: "POST",
data: data,
headers: {
'Content-Type': 'application/json'
}
}).then(function(response) {
if (response.status === 200) $scope.sometext = "200 all good";
else if (response.status === 400) $scope.sometext = "400 nope";
else if (response.status === 404) $scope.sometext = "404";
else if (response.status === 500) $scope.sometext = …Run Code Online (Sandbox Code Playgroud) 嘿家伙我有一个MySQL查询,减少每按一次按钮的库存,
询问
UPDATE Animals
SET Stock = Stock - 1
WHERE Specie ='{1}' and Country ='{0}'
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问题是我希望它停在0并且不进入否定是否有办法做到这一点?
我的代码中有一些错误,由于某种原因,当我试图抓住最后它会抛出错误,说它缺少很多括号,尽管我认为不是.有人可以让我知道我哪里出错了.
码:
namespace login
{
public partial class _Default : Page
{
// decleration of tabels and dataadapters including my connection string for my MySQL databse
DataSet ds = new DataSet();
MySqlConnection cs = new MySqlConnection(@"SERVER= ********;username=******;password=******;Allow Zero Datetime=true; Initial Catalog = benoatsc_GreenFilm");
MySqlDataAdapter da = new MySqlDataAdapter();
DataTable dt = new DataTable();
String totalDonations = string.Empty;
protected void Button1_Click(object sender, EventArgs e)
{
try
{
MySqlCommand SelectCommand = new MySqlCommand("select * from films.user where user_name='" + this.username.Text + "; …Run Code Online (Sandbox Code Playgroud) 我可以把它变成一个开关声明吗?
if (donation_euro.Text.Trim().Equals(""))
{
donation_euro.Text = "00.00";
}
if (donation_lui.Text.Trim().Equals(""))
{
donation_lui.Text = "00.00";
}
if (donation.Text.Trim().Equals(""))
{
donation.Text = "00.00";
}
Run Code Online (Sandbox Code Playgroud) 我有三张桌子:
department,employee和telephone
employee有列EmpNo,Surname,Firstname和DeptNo.
telephone有列EmpNo和Extension.
department有列DeptNo和DeptName.
我想要的是全名,部门名称和电话分机.
我想我差不多了,但还没有工作.
我的查询
SELECT e.Firstname, e.Surname, d.DeptName, t.Extension
FROM employee AS e
INNER JOIN department AS d
INNER JOIN telephone AS t
ON e.DeptNo = d.DeptNo
ON t.EmpNo = e.EmpNo;
Run Code Online (Sandbox Code Playgroud) 我是php的新手,我的代码出错,并且在识别错误时遇到问题.
错误说:
解析错误:第12行上的/home/ob219/public_html/membership/classes/DB.php中的语法错误,意外的'(',期望标识符(T_STRING)或变量(T_VARIABLE)或'{'或'$'
它可能只是我没有看到一个简单的错误,但如果它没有,如果我的代码的逻辑有一个缺陷,我会恳请一些帮助解释问题.谢谢.
和代码是:
<?php
class DB {
private static $_instance = null;
private $_pdo,
$_query,
$_error = false,
$_results,
$_count = 0;
private function __construct() {
try {
$this->_pdo = new PDO('mysql:host=' . config::get('mysql/host') . ';dbname=' . config::('mysql/db'), config::get('mysql/username'), config::get('mysql/password'));
} catch(PDOException $e) {
die($e->getMessage());
}
}
public static function getInstance() {
if(!isset(self::$_instance)) {
self::$_instance = new DB();
}
return self::$_instance;
}
}
Run Code Online (Sandbox Code Playgroud) 我的模型中有一个查询,我需要在视图中打印数据
模型
function get_bank()
{
$query = $this->db->query("SELECT
(
12* (YEAR('account_add_date') - YEAR('start_date')) +
(MONTH('account_add_date') - MONTH('start_date'))
) AS differenceInMonth
->FROM ('bank')
WHERE mem_id = '".$this->session->userdata('id')."'");
return $query->result();
$data['account_age'] = $query->row_array();
}
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我试图在我的模型中打印输出,但它不起作用,我不知道我哪里出错了.我是MVC的新手并且仍然习惯它.
视图
<h2>age of account</h2>
<?php
$age = $this->model('profiles_model' , $data );
print "<h2>$age</h2>";
?>
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调节器
function index()
{
$data = array();
$this->load->model('user_profile/profiles_model');
$query = $this->profiles_model->get_bank();
if(!empty($query))
{
$data['records'] = $query;
}
$this->load->view('profile_view', $data);
}
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