如何在C中的字符串文字中存储私钥?
例如
-----BEGIN RSA PRIVATE KEY-----
MIIBOgIBAAJBANuwDJCXuv/FszouyCcDNIn6++/8EtdVpzvLKpqLdK/fq6Y3bIjD
6fPVCNwANeJsSHKexi4qPkBpZ8/C0Ssnp48CAwEAAQJAHtDmIk42W/R2fJ3dU6Oe
dhBv0K0SU4RfTgLkugL/3j+GIQCiFXBkfO/eG6J8vQlOQaGbK7Zu6bSnCoCdiDmR
sQIhAPysf1AIbRoQGO6HYtAoTUOMlih7dyh4O3jKCqQUa60XAiEA3pRju0/0g2JK
bdSct/kqii1o+RydH79WCnKVgVvulEkCIFdbRADliOLT4erFv/H7nQrXliqU1ROW
zejq4VbtAHUtAiBRP5OkRYx5BUEsFGdc1MyNggQGo0ZL13ld+PPQM7HEWQIhAIU1
InlMgmqV1GzEXsAwRH5RH2zEqAe9mKkU7SZWT0rI
-----END RSA PRIVATE KEY-----
Run Code Online (Sandbox Code Playgroud)
由于精度,0.1 + 0.2不等于0.3大多数编程语言。然而,
var float a, float b
assert(a != 0 && b != 0)
if a / b == -1.0 {
// a, b are opposite numbers:
// abs(a) == abs(b) && (a > 0 && b < 0 || a < 0 && b > 0)
...
}
Run Code Online (Sandbox Code Playgroud)
如果非零并且是相反的数(它们的绝对值相同,但一个是正数,另一个是负数),它总是正确的吗?ab
或者我必须引入一个非常小的数字epsilon(例如1e-7)来消除错误:
if a / b >= -1.0 - epsilon && a / b <= -1.0 + epsilon
Run Code Online (Sandbox Code Playgroud)