小编msa*_*man的帖子

如何使用php导入mysql数据库中的.sql文件

我怎么能这样做,请帮我解决这个问题谢谢

此代码显示此错误..

There was an error during import. Please make sure the import file is saved in the same folder as this script and check your values:

MySQL Database Name:    test
MySQL User Name:    root
MySQL Password: NOTSHOWN
MySQL Host Name:    localhost
MySQL Import Filename:  dbbackupmember.sql

我正在使用此代码

<?php
//ENTER THE RELEVANT INFO BELOW
$mysqlDatabaseName ='test';
$mysqlUserName ='root';
$mysqlPassword ='';
$mysqlHostName ='localhost';
$mysqlImportFilename ='dbbackupmember.sql';
//DONT EDIT BELOW THIS LINE
//Export the database and output the status to the page
$command='mysql …

我想在单击编辑按钮时更新我的​​表单，然后所有信息都正确显示，但状态值始终显示相同的打开选项。我不知道为什么它显示相同的打开状态，而我当前的状态已完成，但它始终显示打开，请帮助我解决此问题，谢谢

这是我的表单代码用户名显示正确但状态显示不正确

 <p><label class="field" for="username">UserName:</label>
     <input name="username" type="text" id="username"  value="<?php echo $username; ?>" size="50" />
   </p>
  <p>

                <label class="field" for="Status">Status</label>
                    <select name="status" id="status" value="<?php echo $status; ?>"  >
                        <option value="open">Open</option>
                        <option value="done">Done</option>
                        <option value="pending">Pending</option>
                        <option value="working">Working</option>
                    </select>
       </p>

这显示了这样的结果 70.479

我想要这样的结果 70.500

我该怎么做，请帮我解决这个问题，谢谢

<?php //Starting of php 
    if(isset($_POST['submit']))//if the submit button has pressed
    {
    $first = $_POST['first']; //Getting Value of first integer from add.html
    $sec = $_POST['sec']; //Getting Value of Second integer from add.html
    $res = $first * $sec *75 /365 /30; //Adding the two values and placing the added result to 'res' variable
    echo 'Added Result:';
    echo "<br>Rounded value of the number = ".round($res,3); 

    }
    //Ending of php
    ?>