小编Dev*_*ero的帖子

所以我终于让我的应用程序工作到它获得JSON请求的正确URL.但是现在我无法使用该URL.

我知道该服务正在从Google Maps API返回承诺,我可能不应该这样做,但如果我将其删除,我会收到"Weather.getWeather is undefined"错误.我不知道为什么.

我怎样才能让它正常工作.谢谢你的帮助.

weatherService.getWeather = function(city)  {


        var coordsUrl = 'https://maps.googleapis.com/maps/api/geocode/json?address=' + city;


        return $http.get(coordsUrl)
            .success(function(data) {
                var coords = data.results[0].geometry.location.lat + ',' + data.results[0].geometry.location.lng;

            return getWeatherData(coords);  

        }); 

function getWeatherData(coords)  {
            var deferred = $q.defer(),
            apiKey = 'cbbdddc644184a1d20ffc4a0e439650d',
            weatherUrl = 'https://api.forecast.io/forecast/' + apiKey + '/' + coords + '?callback=JSON_CALLBACK';


            $http.jsonp(weatherUrl)
                .success(function(data) {

                    deferred.resolve(data);

                }).error(function(err) {

                    deferred.reject(err);

                });

            console.log(weatherUrl);

            return deferred.promise;
        }        

    };

控制器:

vm.fetchWeather = function(city) {

    Weather.getWeather(city)
        .then(function(data) {
            console.log(data);
            vm.place = data;
    });
};