小编use*_*070的帖子

我使用下面的代码找到一个字符串std::vector的string类型.但是如何返回特定元素的位置？

码:

#include <iostream>
#include <algorithm>
#include <vector>

using namespace std;

int main() {
    vector<string> vec;
    vector<string>::iterator it;

    vec.push_back("H");
    vec.push_back("i");
    vec.push_back("g");
    vec.push_back("h");
    vec.push_back("l");
    vec.push_back("a");
    vec.push_back("n");
    vec.push_back("d");
    vec.push_back("e");
    vec.push_back("r");

    it=find(vec.begin(),vec.end(),"r");
    //it++;

    if(it!=vec.end()){
        cout<<"FOUND AT : "<<*it<<endl;
    }
    else{
        cout<<"NOT FOUND"<<endl;
    }
    return 0;
}

输出:

FOUND AT : r

预期产出:

FOUND AT : 9

我使用以下代码替换system dateWindows操作系统中的格式的特殊字符.

但我只能替换一个角色.

码:

#include <iostream>
#include <string>
using namespace std;

int main ()
{
    string str("10/16/13");
    string str2("/");
    str.replace(str.find(str2),str2.length(),"-");
    cout << str << endl;
    return 0;
}

输出:

10-16/13

这段代码在哪里做错了？我只需要char类型,请不要建议使用std::string.

#include <iostream>
#include <string.h>
using namespace std;

int main() 
{
    char *mystring="C:/windows";
    char last_char;
    last_char = mystring[strlen(mystring)-1];
    cout<<"Input: " <<mystring<<endl;
    if(strcmp(last_char,";")!=0)
    {
        strcat(mystring,";");
    }
    cout<<"Output: "<<mystring<<endl;
    return 0;
}

输出:

    Compilation error    time: 0 memory: 3340 signal:0
prog.cpp: In function ‘int main()’:
prog.cpp:7:17: warning: deprecated conversion from string constant to ‘char*’ [-Wwrite-strings]
  char *mystring="C:/windows";
                 ^
prog.cpp:11:25: error: invalid conversion from ‘char’ to ‘const char*’ [-fpermissive]
  if(strcmp(last_char,";")!=0)
                         ^
In file included from prog.cpp:2:0:
/usr/include/string.h:140:12: error:   initializing …