我是Kafka的新手,我创建了一个名为的主题 Hell0-Kafka3
现在我想删除它.所以我发出这样的命令:
$ bin/kafka-topics.sh --zookeeper localhost:2181 --delete --topic Hello-Kafka3
Topic Hello-Kafka3 is marked for deletion.
Note: This will have no impact if delete.topic.enable is not set to true.
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有人可以帮我理解注意:在最后一行?
要在AWS中从2节点集群中删除节点,我运行了
nodetool removenode <Host ID>
此后,我应该让我的集群回来,如果我把所有的cassandra.yaml和cassandra-rackdc.properties正确的.我做了但仍然,我无法恢复我的群集.
nodetool status 只显示一个节点.
cassandra上的重要system.log是:
INFO [main] 2017-08-14 13:03:46,409 StorageService.java:553 - Cassandra version: 3.9
INFO [main] 2017-08-14 13:03:46,409 StorageService.java:554 - Thrift API version: 20.1.0
INFO [main] 2017-08-14 13:03:46,409 StorageService.java:555 - CQL supported versions: 3.4.2 (default: 3.4.2)
INFO [main] 2017-08-14 13:03:46,445 IndexSummaryManager.java:85 - Initializing index summary manager with a memory pool size of 198 MB and a resize interval of 60 minutes
INFO [main] 2017-08-14 13:03:46,459 MessagingService.java:570 - Starting Messaging Service on …Run Code Online (Sandbox Code Playgroud) 我有 au 用户,其密码中包含特殊字符。密码是123@456。我试图逃避这个角色,但仍然不起作用。下面是我尝试过的方法:
$ mongo mongodb://user5:123%40456@localhost:28017/admin
MongoDB shell version v3.4.0
connecting to: mongodb://user5:123%40456@localhost:28017/admin
2017-02-14T12:11:47.571+1100 E QUERY [main] Error: Authentication failed. :
connect@src/mongo/shell/mongo.js:234:13
@(connect):1:6
exception: connect failed
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我可以使用以下方式进行连接:
$ mongo mongodb://localhost:28017/admin -u user5 -p 123@456
MongoDB shell version v3.4.0
connecting to: mongodb://localhost:28017/admin
MongoDB server version: 3.4.0
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但我正在寻找一种通过 URI 进行连接的方法。如何@在 MongoDB 中使用该字符作为 URI 连接中的密码?这样,我可以使用相同的 URI 进行 shell 连接和驱动程序连接。
在生产服务器上,我被迫使用 python3.2。可悲的是,我的几个依赖项需要>=python3.4. 有没有办法找出可以与特定 python 版本一起使用的包的最新版本?
例如, with python3.2,numpy应该使用什么版本?
(这只是一个例子,理想情况下答案不会集中在例子上,而是在实际问题上)。
我正在使用 kafka、zookeeper 和 kafka-manager 来管理集群。
我有 3 个节点集群。在我从一开始就设置的所有集群中delete.topic.enable=true
现在,当我想删除一个主题时,它显示以下错误。
topicxyz - marked for deletion
但它没有被删除。
我也尝试从 kafka-manager 中删除,它说
Yikes! KeeperErrorCode = NodeExists for /admin/delete_topics/topicxyz
错误日志:
卡夫卡经理:
[ESC[31merrorESC[0m] k.m.ApiError$ - error : KeeperErrorCode = NodeExists for /admin/delete_topics/topicxyz
org.apache.zookeeper.KeeperException$NodeExistsException: KeeperErrorCode = NodeExists for /admin/delete_topics/topicxyz
at org.apache.zookeeper.KeeperException.create(KeeperException.java:119) ~[org.apache.zookeeper.zookeeper-3.4.6.jar:3.4.6-1569965]
at org.apache.zookeeper.KeeperException.create(KeeperException.java:51) ~[org.apache.zookeeper.zookeeper-3.4.6.jar:3.4.6-1569965]
at org.apache.zookeeper.ZooKeeper.create(ZooKeeper.java:783) ~[org.apache.zookeeper.zookeeper-3.4.6.jar:3.4.6-1569965]
at org.apache.curator.framework.imps.CreateBuilderImpl$11.call(CreateBuilderImpl.java:721) ~[org.apache.curator.curator-framework-2.10.0.jar:na]
at org.apache.curator.framework.imps.CreateBuilderImpl$11.call(CreateBuilderImpl.java:704) ~[org.apache.curator.curator-framework-2.10.0.jar:na]
at org.apache.curator.RetryLoop.callWithRetry(RetryLoop.java:108) ~[org.apache.curator.curator-client-2.10.0.jar:na]
at org.apache.curator.framework.imps.CreateBuilderImpl.pathInForeground(CreateBuilderImpl.java:701) ~[org.apache.curator.curator-framework-2.10.0.jar:na]
at org.apache.curator.framework.imps.CreateBuilderImpl.protectedPathInForeground(CreateBuilderImpl.java:477) ~[org.apache.curator.curator-framework-2.10.0.jar:na]
at org.apache.curator.framework.imps.CreateBuilderImpl.forPath(CreateBuilderImpl.java:467) ~[org.apache.curator.curator-framework-2.10.0.jar:na]
at org.apache.curator.framework.imps.CreateBuilderImpl.forPath(CreateBuilderImpl.java:447) ~[org.apache.curator.curator-framework-2.10.0.jar:na]
[ESC[37minfoESC[0m] k.m.a.KafkaManagerActor - Updating internal state... …Run Code Online (Sandbox Code Playgroud) 我正在尝试使用 kafka,MultiProcessConsumer但出现以下错误。似乎错误与python中的多线程有关
这是我正在使用的代码。
simple.py
from kafka import SimpleProducer, SimpleClient, SimpleConsumer, MultiProcessConsumer
# To consume messages
client = SimpleClient('localhost:9092')
consumer = MultiProcessConsumer(client, "my-group", "testing_topic", num_procs=3)
for message in consumer:
# message is raw byte string -- decode if necessary!
# e.g., for unicode: `message.decode('utf-8')`
print(message)
client.close()
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运行上述代码时出错。
$ python simple.py
Error in atexit._run_exitfuncs:
Traceback (most recent call last):
File "/var/users/ec2-user/.pyenv/versions/3.6.0/lib/python3.6/multiprocessing/managers.py", line 749, in _callmethod
conn = self._tls.connection
AttributeError: 'ForkAwareLocal' object has no attribute 'connection'
During handling of the above …Run Code Online (Sandbox Code Playgroud) python python-3.x apache-kafka kafka-consumer-api kafka-python
我是 vuejs 的新手,我收到以下错误:错误:
[Vue warn]: Failed to mount component: template or render function not defined.
found in
---> <Anonymous>
<Vcinfo> at resources/assets/js/valuechain/Vcinfo.vue
<Root>
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Vcinfo.vue
<template>
<div id="root">
<div class="navbar navbar-default">
<div class="navbar-brand">
<router-link to="/vc">VALUECHAIN</router-link>
</div>
<ul class="nav navbar-nav navbar-left">
<li><router-link to="/vc/setting_keywords">Keywords Setting</router-link></li>
<li><router-link to="/vc/keyword_search">Search Keywords</router-link></li>
</ul>
</div>
<router-view></router-view>
</div>
</template>
<style lang="css">
.navbar {
margin-top:15px;
}
</style>
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vc.js
import Vue from 'vue'
import Vcinfo from './Vcinfo.vue'
import router from './router'
const app = new Vue({
el: '#vc',
components: { Vcinfo …Run Code Online (Sandbox Code Playgroud) vuejs我想使用和转到特定选项卡element-ui。这是 jsfiddle 文件。https://jsfiddle.net/hutsu1zf/10/
默认情况下它会降落到第一个选项卡。在页面加载事件时如何登陆任何其他选项卡。我是 vuejs 新手,所以即使有一些提示也将不胜感激。
Python词典具有key独特性.但我正在努力编写(找到)支持以下内容的DS:
例1:
|------|-----------------|
| abc | matched in abcD |
|------|-----------------|
| match| matched in abcD |
|------|-----------------|
| abc | abc found again |
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如果下一个条目如下:
|-----|-----------------|
| abcd| matched in abcD | ----> should replace first entry because abc is substring of abcd.
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所以条目/表应该是这样的
|------|-----------------|
| abcd | matched in abcD |
|------|-----------------|
| match| matched in abcD |
|------|-----------------|
| abc | abc found again |
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有什么建议 ?
可能的功能定义
def substring_value_confirm(keys, values):
# implement as …Run Code Online (Sandbox Code Playgroud) 我试图找到下面代码的复杂性,因为for循环它将是O(n*complexity_of_map.merge)
public int solution(int K, int[] A) {
Map<Integer, Integer> map = new HashMap<Integer, Integer>();
for(int i =0; i < A.length; i++){
map.merge(K - A[i], 1, Integer::sum);
}
return Arrays.stream(A).map(element -> map.getOrDefault(element,0)).sum();
}
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有人可以帮我理解上面代码和map.merge()
Java 8中的时间复杂度.
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