小编Pra*_*apB的帖子

是否有要检测的rails函数["", "", ...](即只包含空字符串或字符串的数组)为空

我的要求:

[""].foo? =>是的

["", ""].foo? =>是的

["lorem"].foo? =>假

["", "ipsum"].foo? =>假

我试过用array.reject!(&:empty?).blank?.它工作,但这改变了我的阵列.我不希望我的阵列被改变.请帮我找一个紧凑的方法.

我是socket编程的新手......我试过这个服务器端程序

#define BUFLEN 512
#define MYPORT 3456
void errorp(char* msg)
{
        perror(msg);
        exit(1);
}

int main()
{
        struct sockaddr_in server, client;
        int sock;
        int slen = sizeof(server);
        int clen = sizeof(client);
        char *recvbuf, senbuf[BUFLEN] = {'h','e','l','l','o'};

        if((sock = socket(AF_INET, SOCK_DGRAM, 0) == -1))
                errorp("Socket creation failed");


        printf("To the client: %s, %s", senbuf, " World");
        bzero(&server, sizeof(server));

        server.sin_family = AF_INET;
        server.sin_port = MYPORT;
        server.sin_addr.s_addr = inet_addr("127.0.0.1");
        if(bind(sock, (struct sockaddr*)&server, slen)==-1)
                errorp("Socket Bind Failed");
        if(recvfrom(sock, recvbuf, sizeof(recvbuf), 0, (struct sockaddr*) &client, &clen) …