小编Spe*_*cer的帖子

我是Android编程新手,我有一个ListView,当过滤总是返回列表中的第一项,所以我该如何解决这个问题？

例如,我的列表包含AA,AB,AC,BC,BD当我想在列表中搜索以B开头的内容时,我将获得BC,BD但是当我点击BC时,它返回AA和BD,它返回给我AB

public class PatientList extends Activity{

PatientDB patientDB;
Context myContext;
ListView lv_patients;    
EditText et_patients;
ArrayAdapter<String> adapter;   
ArrayList<HashMap<String, String>> patientList;
static String value;
String[] patientarray = new String[]{"initials"};
ArrayList<String> patientArrayList = new ArrayList<String>();

@Override
protected void onCreate(Bundle savedInstanceState) {
    // TODO Auto-generated method stub
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_patient_list);

    myContext = this;
    patientDB = new PatientDB(myContext);
    patientDB.open();

    Cursor patientCursor;

    patientCursor = patientDB.retrieveAllEntriesCursor();

    if(patientCursor!=null && patientCursor.getCount()>0)
    {
        String patientInitials;

        patientCursor.moveToFirst();
        do 
        {
            patientCursor.getString(patientDB.COLUMN_KEY_ID); // + " " + 
            patientInitials = patientCursor.getString(patientDB.COLUMN_INITIALS_ID);
            Log.i("FromCursor", patientInitials);
            patientArrayList.add(patientInitials); …