也许有人可以帮我解决我遇到的这个小问题.我试图在没有页面刷新的情况下提交此表单.但它会跳过帖子并直接转到ajax调用.我想我想念了preventDefault().我在网上搜索但无法找到我需要的东西.非常感谢您的帮助或指向另一个表单提交.
HTML下面:
<!DOCTYPE html>
<html>
<head>
<title>AJAX | Project</title>
<link href="project.css" rel="stylesheet"/>
<script src="jquery.js"></script>
</head>
<body>
<div id="mainCon">
<h1>Contact Book</h1>
<div id="form_input">
<form id="myform" method="post" action="addrecord.php">
<label for="fullname">Name:</label>
<input type="text" name="fullname" id="fullname"/><span id="NameError"> </span>
<br/>
<label for="phonenumber">Phone Number:</label>
<input type="text" id="phonenumber" name="phonenumber"><span id="PhoneError"></span>
<br />
<input id="buttton" type="submit" onClick="addnumber()" value="Add Phone Number"/>
<input type="button" id="show" value="the Results"/>
</form>
</div>
<div id="form_output">
</div>
</div>
<script src="project.js"></script>
<script type="text/javascript">
function addnumber(){
var Fullname = document.getElementById("fullname").value;
var Phonenumber = document.getElementById("phonenumber").value;
if(Fullname == ""){ …我尝试了很多不同的方法,但我无法从数组中取消设置变量.我开始用一个字符串将它爆炸成一个数组,现在我要删除Bill.我错过了一些东西？我访问过php.net和我,仍然卡住了......
<!DOCTYPE html>
<html>
<head>
<title></title>
</head>
<body>
<?php
$names = "Harry George Bill David Sam Jimmy";
$Allname = explode(" ",$names);
unset($Allname['Bill']);
sort($Allname);
$together = implode("," ,$Allname);
echo "$together";
?>
</body>
</html>