当我运行此代码.
#include <stdio.h>
void moo(int a, int *b);
int main()
{
int x;
int *y;
x = 1;
y = &x;
printf("Address of x = %d, value of x = %d\n", &x, x);
printf("Address of y = &d, value of y = %d, value of *y = %d\n", &y, y, *y);
moo(9, y);
}
void moo(int a, int *b)
{
printf("Address of a = %d, value of a = %d\n", &a, a);
printf("Address of b = %d, value of b …Run Code Online (Sandbox Code Playgroud) 这可能听起来很傻......但我不知道在哪里可以找到JOGL JAR.我搜索了他们的网站(http://jogamp.org/jogl/www/)并找不到它.
有人可以帮忙吗?
谢谢
blargman
为什么每当我必须使用awakeFromNib协议时,我必须将它放在这种格式中?
-(void)awakeFromNib
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有什么需要 - (无效)?
如果我的字符串在此程序中超过9个字符,我不应该收到错误吗?
// CString.c
// 2.22.11
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
main()
{
char *aString = calloc(10, sizeof(char));
if (aString == NULL)
{
return 1;
}
printf("PLEASE ENTER A WORD: ");
scanf("%s", aString);
printf("YOU TYPED IN: %s\n", aString);
//printf("STRING LENGTH: %i\n", strlen(aString));
}
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谢谢
blargman