这是我的代码片段.
int main()
{
int *var = new int(6);
cout<<"Hello\n";
delete var;
return 0;
}
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当用mudflap编译时
$export MUDFLAP_OPTIONS="-print-leaks -mode-check"
$g++ test.cpp -fmudflap -lmudflap
$./a.out
Segmentation fault (core dumped)
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但是在没有mudflap选项的情况下进行编译时,它不会抛出核心转储.我是mudflap的新手.请告诉我是否以错误的方式使用mudflap.
供参考:
$uname -a
Linux localhost.localdomain 2.6.18-308.4.1.el5 #1 SMP Wed Mar 28 01:54:56 EDT 2012 x86_64 x86_64 x86_64 GNU/Linux
$g++ -v
Using built-in specs.
COLLECT_GCC=g++
COLLECT_LTO_WRAPPER=/usr/libexec/gcc/x86_64-redhat-linux-gnu/4.7.3/lto-wrapper
Target: x86_64-redhat-linux-gnu
Configured with: /root/rohit/gcc-4.7.3/configure --prefix=/usr/
Thread model: posix
gcc version 4.7.3 (GCC)
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充满了coredump
核心由`./a.out'生成.
Program terminated with signal 11, Segmentation fault.
[New process 22176]
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