小编Sid*_*idh的帖子

需要建议,如何打开一个twitter bootstrap模式,从Asp.net Webform代码背后？

我想根据保存时的某些要求打开模态.一旦用户单击保存按钮,它将在后面的代码中运行验证,如果有任何验证错误,则在引导模式对话框中显示所有错误.这一切都应该在保存按钮单击时发生.

我尝试使用下面的代码,但它提示我java脚本错误"错误:对象不支持属性或方法'模态'".谢谢

Asp.Net Webforms 4.5

Bootstrap V3.0.1

jQuery的1.9.0.js

jQuery的UI,1.8.24.js

Default.aspx 

<asp:Content runat="server" ID="DisplayContent" ContentPlaceHolderID="DisplayContent">
<div class="container">
</div>
</asp:Content>

<asp:Content runat="server" ID="BodyContent" ContentPlaceHolderID="MainContent">

<div class="container">
    <div class="btn-group">
        <asp:Button ID="btnSubmit" class="btn-info" runat="server" Text="Submit"          
        OnClick="btnSubmit_Click"></asp:Button>
    </div>
</div>


<%--Bootstrap Modal Dialog--%>
<div class="modal fade" id="myModal" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true">
    <div class="modal-dialog">
        <div class="modal-content">
            <div class="modal-header">
                <button type="button" class="close" data-dismiss="modal" aria-hidden="true">&times;</button>
                <h4 class="modal-title">Validation Errors List for HP7 Citation</h4>
            </div>
            <div class="modal-body">
            </div>
            <div class="modal-footer">
                <button class="btn btn-info" data-dismiss="modal" aria-hidden="true">Close</button>
            </div>
        </div>
    </div>
</div> …