小编Pan*_*ver的帖子

我一直在尝试使用Android内置的MediaPlayer类来流式传输mp3.文档会告诉我,这应该像以下一样简单:

MediaPlayer mp = new MediaPlayer();
mp.setDataSource(URL_OF_FILE);
mp.prepare();
mp.start();

但是我反复得到以下内容.我也尝试过不同的URL.请不要告诉我流式传输不适用于mp3.

E/PlayerDriver(   31): Command PLAYER_SET_DATA_SOURCE completed with an error or info PVMFErrNotSupported
W/PlayerDriver(   31): PVMFInfoErrorHandlingComplete
E/MediaPlayer(  198): error (1, -4)
E/MediaPlayer(  198): start called in state 0
E/MediaPlayer(  198): error (-38, 0)
E/MediaPlayer(  198): Error (1,-4)
E/MediaPlayer(  198): Error (-38,0)

任何帮助非常感谢,谢谢S

我们AsyncTasks用来访问数据库表和游标.

不幸的是,我们偶尔会看到有关数据库被锁定的例外情况.

E/SQLiteOpenHelper(15963): Couldn't open iviewnews.db for writing (will try read-only):
E/SQLiteOpenHelper(15963): android.database.sqlite.SQLiteException: database is locked
E/SQLiteOpenHelper(15963):  at     android.database.sqlite.SQLiteDatabase.native_setLocale(Native Method)
E/SQLiteOpenHelper(15963):  at     android.database.sqlite.SQLiteDatabase.setLocale(SQLiteDatabase.java:1637)
E/SQLiteOpenHelper(15963):  at     android.database.sqlite.SQLiteDatabase.<init>(SQLiteDatabase.java:1587)
E/SQLiteOpenHelper(15963):  at android.database.sqlite.SQLiteDatabase.openDatabase(SQLiteDatabase.java:638)
E/SQLiteOpenHelper(15963):  at android.database.sqlite.SQLiteDatabase.openOrCreateDatabase(SQLiteDatabase.java:659)
E/SQLiteOpenHelper(15963):  at android.database.sqlite.SQLiteDatabase.openOrCreateDatabase(SQLiteDatabase.java:652)
E/SQLiteOpenHelper(15963):  at android.app.ApplicationContext.openOrCreateDatabase(ApplicationContext.java:482)
E/SQLiteOpenHelper(15963):  at android.content.ContextWrapper.openOrCreateDatabase(ContextWrapper.java:193)
E/SQLiteOpenHelper(15963):  at android.database.sqlite.SQLiteOpenHelper.getWritableDatabase(SQLiteOpenHelper.java:98)
E/SQLiteOpenHelper(15963):  at android.database.sqlite.SQLiteOpenHelper.getReadableDatabase(SQLiteOpenHelper.java:158)
E/SQLiteOpenHelper(15963):  at com.iview.android.widget.IViewNewsTopStoryWidget.initData(IViewNewsTopStoryWidget.java:73)
E/SQLiteOpenHelper(15963):  at com.iview.android.widget.IViewNewsTopStoryWidget.updateNewsWidgets(IViewNewsTopStoryWidget.java:121)
E/SQLiteOpenHelper(15963):  at com.iview.android.async.GetNewsTask.doInBackground(GetNewsTask.java:338)
E/SQLiteOpenHelper(15963):  at com.iview.android.async.GetNewsTask.doInBackground(GetNewsTask.java:1)
E/SQLiteOpenHelper(15963):  at android.os.AsyncTask$2.call(AsyncTask.java:185)
E/SQLiteOpenHelper(15963):  at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:256)
E/SQLiteOpenHelper(15963):  at java.util.concurrent.FutureTask.run(FutureTask.java:122)
E/SQLiteOpenHelper(15963):  at java.util.concurrent.ThreadPoolExecutor$Worker.runTask(ThreadPoolExecutor.java:648)
E/SQLiteOpenHelper(15963):  at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:673)
E/SQLiteOpenHelper(15963):  at java.lang.Thread.run(Thread.java:1060)

有没有人有一个代码的一般例子,它从一个读取的不同线程写入数据库,我们如何确保线程安全. …

我正在尝试为我的应用程序创建共享扩展,这需要从扩展程序登录Google.我已经设置了共享组密钥链,并且能够从主应用程序写入并读取扩展目标.但我无法从扩展程序登录Google,因为GIDSignIn.sharedInstance().hasAuthInKeychain()始终返回false.

有没有办法从扩展程序登录Google,我该怎么做？任何帮助,将不胜感激.

我无法将动画应用于视图.我试图从CursorAdapter的构造函数内部加载动画,所以我可以稍后将其设置为列表中的某些子项.

在构造函数中我有:

shineAnimation = AnimationUtils.loadAnimation(ctx, R.anim.news_list_item_shine);

动画在我的res/anim目录中

<?xml version="1.0" encoding="utf-8"?>
<animation-list xmlns:android="http://schemas.android.com/apk/res/android" android:oneshot="true">
    <item android:drawable="@drawable/shine1" android:duration="200" />
    <item android:drawable="@drawable/shine2" android:duration="200" />
    <item android:drawable="@drawable/shine3" android:duration="200" />
    <item android:drawable="@drawable/shine4" android:duration="200" />
    <item android:drawable="@drawable/shine5" android:duration="200" />
</animation-list>

我得到一个例外:未知的动画名称:动画列表

非常感谢帮助

谢谢S.