class Employee
{
public static $favSport = "Football";
public static function watchTV()
{
echo "Watching ".static::$favSport;
}
}
class Executive extends Employee
{
public static $favSport = "Polo";
}
echo Executive::watchTV();
解析错误:语法错误,第7行意外T_STATIC
为什么我会得到解析错误以及如何修复它？谢谢!
当我尝试启动服务时,我得到了
~$ sudo service mongodb start
mongodb start/running, process 20221
但它并没有真正开始〜$ sudo服务mongodb状态mongodb停止/等待
这可能是因为我的dbpath不是默认的,所以如何使用非默认的dbpath启动服务
它给了我空白页...
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
{if $tplSeoFile}{include file="$modulePath/$tplSeoFile"}{/if}
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<meta name="Author" content="" />
<meta name="Robots" content="index, follow" />
<meta name="Revisit-after" content="10 days" />
<link rel="stylesheet" href="img/cms/css/reset.css" type="text/css" media="all" />
<link rel="stylesheet" href="img/cms/css/960.css" type="text/css" media="all" />
<link rel="stylesheet" href="img/cms/css/master.css" type="text/css" media="all" />
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function() {
//Default Action
$(".tab_content").hide(); //Hide all content
$("ul.tabs li:first").addClass("active").show(); //Activate first tab
$(".tab_content:first").show(); //Show first tab content
//On Click Event
$("ul.tabs li").click(function() …我不想打破我的应用程序......
有人尝试过:
"--laf javax.swing.plaf.metal.MetalLookAndFeel --fontsize 14 -J-Dswing.aatext = true -J-Dswing.metalTheme = steel -J-Dswing.plaf.metal.controlFont = Dialog-plain-14"在位于/opt/netbeans/etc/netbeans.conf的Netbean配置文件中的netbeans_default_options中
？
致命错误:在线上的非对象上调用成员函数query():$ result = $ conn-> query($ sql)或die(mysqli_error());
谁知道什么是错的以及如何解决它？
<?php
function dbConnect($usertype, $connectionType = 'mysqli') {
$host = 'localhost';
$db = 'phpsols';
if ($usertype == 'read') {
$user = 'psread';
$pwd = '123';
} elseif ($usertype == 'write') {
$user = 'pswrite';
$pwd = '123';
} else {
exit('Unrecognized connection type');
}
if ($connectionType == 'mysqli') {
return new mysqli($host, $user, $pwd, $db) or die ('Cannot open database');
} else {
try {
return new PDO("mysql:host=$host;dbname=$db", $user, $pwd);
} catch (PDOException …我有
return $ query;
功能在我的模型中.我怎样才能将它传递给视图？
我的方法是:
public function findByTypes($ data = array()){$ this-> Type-> Behaviors-> attach('Containable',array('autoFields'=> false)); $这 - >型 - > Behaviors->连接( 'Search.Searchable');
Run Code Online (Sandbox Code Playgroud)$query = $this->Type->getQuery('all', array( 'conditions' => array('Type.id' => $data['title']), 'fields' => array('id'), 'contain' => array('Ticket') )); return $query; }
我怎样才能获得查询结果？
如何从a和b获取数组c？
$arr_a = array(
'foo' => array(
'bar' => 1,
'baz' => 2,
),
'lorem' => array(
'ipsum' => array(
'dolor' => 'sit',
),
),
'mollis' => 'ultrices',
);
第二个数组看起来像这样:
$arr_b = array(
'foo' => array(
'ante' => 'urna'
),
'lorem' => array(
'ipsum' => array(
'dolor' => 'turpis'
),
),
);
结果数组应该是:
$arr_c = array(
'foo' => array(
'bar' => 1,
'baz' => 2,
'ante' => 'urna',
),
'lorem' => array(
'ipsum' => array(
'dolor' => 'turpis',
),
), …php ×4
cakephp ×1
cakephp-1.3 ×1
javascript ×1
jquery ×1
mongodb ×1
mysqli ×1
netbeans ×1
smarty ×1
ubuntu ×1