一个类可以有几个默认的构造函数吗?我想知道因为我认为任何东西都只能通过"默认"的定义只有一个默认功能,但我不太确定.
我测试了以下程序,没有错误.但每当我输入"hangman"它时,都不会启动if名为的新语句代码块"if response_2".为什么不运行它?
response_2 = raw_input("What would you like to play? Hangman or Word Guess?")
if response_2 == ("Hangman", "hangman"):
print "Running Hangman..."
print "Catching Criminals..."
print "Building Gallows..."
print "Getting that one song boy from Pirate's of the Carribean"
elif response_2 == ("Word_Guess", "word_guess", "word guess", "Word Guess", "Word guess", "word Guess", "Word_guess", "word_Guess"):
print "Not completed yet"
Run Code Online (Sandbox Code Playgroud) 当我尝试运行这个程序时,我继续收到无限循环错误.谁能帮帮我,告诉我为什么?任何援助都将非常感激.谢谢!
void Increment(int);
int main()
{
int count = 1;
while(count < 10)
cout << "the number after " << count; //Increment function
Increment(count); //count+1
cout << " is " << count << endl;
return 0;
}
void Increment (int nextNumber)
{
nextNumber++; //parameter +1
}
Run Code Online (Sandbox Code Playgroud)