小编Ale*_*app的帖子

出于某种原因,我的代码在Visual Studio中工作,但在Linux编译器中没有,并且在Linux中给出了一个错误

test_main.cpp:65: error: no match for 'operator<<' in 'std::operator<<'

在[]我的重载代码中有大量的行

String String::operator + (const String & s) const {
String temp;
temp.head = ListNode::concat(head,s.head);
return temp;
}

我的concat代码

String::ListNode * String::ListNode::concat(ListNode * L1, ListNode * L2)
{
return L1 == NULL ? copy(L2): new ListNode(L1->info, concat(L1->next, L2));
}

代码测试它

String firstString("First");
String secondString("Second");
cout << "+: " << firstString + secondString << endl;

宣言

ostream & operator << (ostream & out, String & l);

身体

ostream & operator << …

由于某种原因,我无法获得字符串数值转换为整数我运行的错误:

Exception in thread "main" java.lang.NumberFormatException: For input string: "6327818260"
    at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
    at java.lang.Integer.parseInt(Integer.java:495)
    at java.lang.Integer.parseInt(Integer.java:527)
    at MyDirectory.getsize(MyDirectory.java:18)
    at a19010.main(a19010.java:79)

Java结果:1

如果我的输入字符串是"6327818260",为什么它不能成为整数？我的代码是

public String getsize()
{
  int intSize = Integer.parseInt(mySize);
  int count = 0;
  String dataType = "";
  while (intSize > 1000)
  {   
   intSize = intSize / 1000;
   count++;
  } 
  switch (count)
  {
    case 0:
    dataType = "Bytes";
    break;
    case 1:
    dataType = "KB";
    break;
    case 2:
    dataType = "MB";
    break;
    case 3:
    dataType = "GB";
    break;
    case 4:
    dataType …