小编Fur*_*ali的帖子

我是Apache CXF和tomcat的新手.我正在尝试构建一个简单的Web服务并将其部署在tomcat上.下面是我的web.xml但是当我尝试使用我的浏览器访问'services'文件夹时,它说没有找到服务.我尝试创建java Web服务客户端,但它也无法找到服务.这可能有什么问题？

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
    <display-name>Sample web service provider</display-name>
    <listener>
        <!-- For Metro, use this listener-class instead: 
             com.sun.xml.ws.transport.http.servlet.WSServletContextListener -->
        <listener-class>
              org.springframework.web.context.ContextLoaderListener
        </listener-class>
    </listener>
    <!-- Remove below context-param element if using Metro -->
    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>
              classpath:META-INF/cxf/cxf.xml
        </param-value>
    </context-param>
    <servlet>
        <servlet-name>WebServicePort</servlet-name>
        <!-- For Metro, use this servlet-class instead: 
             com.sun.xml.ws.transport.http.servlet.WSServlet  -->
        <servlet-class>org.apache.cxf.transport.servlet.CXFServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>WebServicePort</servlet-name>
        <url-pattern>/services/*</url-pattern>
    </servlet-mapping>
    <session-config>
        <session-timeout>60</session-timeout>
    </session-config>
</web-app>