小编use*_*620的帖子

我正在使用一个查询,其中包含"WHERE"子句中的"IF"语句.但PL\SQL Developer在执行时会出现一些错误.任何人都可以帮我正确的查询？这是查询:

SELECT t.first_name,
       t.last_name,
       t.employid,
       t.status
  FROM employeetable t
 WHERE IF status_flag = STATUS_ACTIVE then t.status = 'A'
       IF status_flag = STATUS_INACTIVE then t.status = 'T'
       IF source_flag = SOURCE_FUNCTION then t.business_unit = 'production'
       IF source_flag = SOURCE_USER then t.business_unit = 'users'
   AND t.first_name LIKE firstname
   AND t.last_name LIKE lastname
   AND t.employid LIKE employeeid;

我收到错误"ORA-00920:无效的关系运算符".

放置括号会status_flag = STATUS_ACTIVE导致错误"ORA-00907:缺少右括号"

我在我的页面上实现了一个Bootstrap轮播,由于某种原因,我无法根据Web浏览器的大小重新定位标题文本.

这是我的HTML代码:

<!-- =======================CAROUSEL=========================== -->
<div id="myCarousel" class="carousel slide" data-ride="carousel">
  <!-- Indicators -->
  <ol class="carousel-indicators">
    <li data-target="#myCarousel" data-slide-to="0" class="active"></li>
    <li data-target="#myCarousel" data-slide-to="1"></li>
  </ol>
  <div class="carousel-inner" role="listbox">
    <div class="item active">
      <img class="first-slide" src="img/main-banner.png" alt="First slide">
      <div class="container">
        <div class="carousel-caption">
          <h1>Democratizing the Internet of Things!</h1>
          <p><a class="btn btn-lg btn-primary" href="./index.php?d=splash" role="button">Try Splash</a></p>
        </div>
      </div>
    </div>
    <div class="item">
      <img class="second-slide" src="img/banner-2.png" alt="Second slide">
      <div class="container">
        <div class="carousel-caption">
          <h1>Another Heading!</h1>
        </div>
      </div>
    </div>
  <a class="left carousel-control" href="#myCarousel" role="button" data-slide="prev">
    <span class="glyphicon glyphicon-chevron-left" aria-hidden="true"></span>
    <span …

我有2个表,EMPLOYEEAPP和EMPLOYEEINFO.

我想在SECURITYGROUP列为特定值时搜索EMPLOYEEAPP表以查找EMPLOYID.

然后,我想从EMPLOYEEAPP表中获取EMPLOYID,并使用EMPLOYEEINFO表中的EMPLID列搜索它们对应的名字和姓氏.

SELECT EMPLOYEEAPP.EMPLOYID, EMPLOYEEINFO.FIRST_NAME, EMPLOYEEINFO.LAST_NAME
FROM EMPLOYEEAPP
WHERE EMPLOYEEAPP.SECURITYGROUP = 'ANALYST'
INNER JOIN EMPLOYEEINFO
ON EMPLOYEEAPP.EMPLOYID=EMPLOYEEINFO.EMPLID

我一直收到错误"ORA-00933:SQL命令未正确结束".

任何帮助或见解将不胜感激!

我需要将日期时间发送到API.

我想这样做,但它不起作用.

$startDate = DateTime::createFromFormat('yyyy-MM-dd\THH:mm:ssZ', '2014-06-13 14:30:00');

不幸的是我得到了,2014-06-13T13:30:00.000Z而我需要它采用这种格式:yyyy-MM-ddTHH:mm:ssZ

我不确定我哪里出错了.任何帮助或建议将不胜感激!