我正在使用我的测试在estore中创建产品,并且需要在提交表单后获取URL.
提交按钮后,是否可以在测试范围内获取URL ?
$I->click('#formSubmit');
$I->wait(5); // wait for redirect to new url
$url = $I->someFunctionToGetCurrentUrl()`
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我从控制台运行此测试,而不是从Web浏览器运行,因此我无法访问服务器端的$ _SERVER.
但是,如果我有一些像$I->canSeeCurrentUrlEquals()代码框架中的方法,那么我应该能够以某种方式访问当前的URL ...
怎么做?
我想过滤一个列表,只留下具有唯一长度的第一个元素.我为它编写了一个函数,但我相信应该有一个更简单的方法:
def uniq_len(_list):
from itertools import groupby
uniq_lens = list(set([x for x, g in groupby(_list, len)]))
all_goods = []
for elem in _list:
elem_len = len(elem)
try:
good = uniq_lens.pop([i for i, x in enumerate(uniq_lens) if x==elem_len][0])
if good:
all_goods.append(elem)
except IndexError as _e:
#print all_goods
pass
return all_goods
In [97]: jones
Out[97]: ['bob', 'james', 'jim', 'jon', 'bill', 'susie', 'jamie']
In [98]: uniq_len(jones)
Out[98]: ['bob', 'james', 'bill']
Run Code Online (Sandbox Code Playgroud) 在 reactjs-babel 应用程序中,我尝试使用break时发生了奇怪的行为forEach
var SomeElement = React.CreateClass({
... ,
getMessageStatus: function getMessageStatus(message) {
var states = this.state.messages_states;
var status = undefined;
states.forEach(function (messageEntity) {
if (messageEntity.id == message.id && messageEntity.is_question == message.is_question) {
status = messageEntity.status;
break; // - this is not working
}
});
return status;
},
...
});
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breakCannot determine target for 'break'在 PhpStorm 和 Babel repl 中说它像repl: Unsyntactic break
如何正确使用 break 一样?
试图弄清楚Java中的线程是如何工作的,我只是想通过将它们全部放入数组来限制可执行线程执行,然后检查循环中是否有一些完成并弹出它们,以便有可能产生一个新线程,得到异常在这段代码中:
public class testThread implements Runnable {
public void run () {
try {
Thread.sleep(1000);
} catch(InterruptedException e){}
System.out.println("This is the test thread");
}
public static void main (String args[]) {
int max_threads = 5;
Thread worker;
ArrayList<Thread> all_workers = new ArrayList<Thread>(max_threads );
for (int i =0; i<50; i++) {
if (all_workers.size()<max_threads){
worker = new Thread (new testThread());
all_workers.add(worker);
worker.start();
} else{
System.out.println("i ran all");
while(all_workers.size()>=max_threads){
try{
System.out.println("Waiting for some to finish");
int counter = 0;
for (Thread wrk: all_workers){ …Run Code Online (Sandbox Code Playgroud) babeljs ×1
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