你知道Chrome窗口是如何超级自定义的,不是,它们有一个自定义标题栏,具有自定义的最小化/最大化/关闭按钮.我如何使用WPF执行此操作?
这就是我所拥有的,但它似乎有点多余.也许在Python中更有经验的人知道如何清理它?应该是非常自我解释它做什么.
def complementary_strand(self, strand):
''' Takes a DNA strand string and finds its opposite base pair match. '''
strand = strand.upper()
newstrand = ""
for i in range(0, len(strand)):
if strand[i] == "T":
newstrand += "A"
if strand[i] == "A":
newstrand += "T"
if strand[i] == "G":
newstrand += "C"
if strand[i] == "C":
newstrand += "G"
return newstrand
Run Code Online (Sandbox Code Playgroud) 好的,所以我有一个名为的数据库字段 moderated
这是一个有3个值的ENUM:
approved
denied
unmoderated
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如何编写一个计算每个数量的查询,以便生成此输出:
Approved: 3
Denied: 10
Unmoderated: 23
Run Code Online (Sandbox Code Playgroud) #include <iostream>
#include <stdlib.h>
#include <time.h>
using namespace std;
int twoify(int num, int times)
{
num *= 2;
if (times > 0)
{
times--;
return twoify(num, times);
}
return num;
}
int main()
{
srand(time(NULL));
const int BET = 1;
const int TIMES = 100000;
const int CHANCE = 50;
int wins = 0;
int losses = 0;
int wstreak = 0;
int lstreak = 0;
int cwstreak = 0;
int clstreak = 0;
for (int i = 0; i …
Run Code Online (Sandbox Code Playgroud) 我有一个以下格式的DNA文件:
>gi|5524211|gb|AAD44166.1| cytochrome
ACCAGAGCGGCACAGCAGCGACATCAGCACTAGCACTAGCATCAGCATCAGCATCAGC
CTACATCATCACAGCAGCATCAGCATCGACATCAGCATCAGCATCAGCATCGACGACT
ACACCCCCCCCGGTGTGTGTGGGGGGTTAAAAATGATGAGTGATGAGTGAGTTGTGTG
CTACATCATCACAGCAGCATCAGCATCGACATCAGCATCAGCATCAGCATCGACGACT
TTCTATCATCATTCGGCGGGGGGATATATTATAGCGCGCGATTATTGCGCAGTCTACG
TCATCGACTACGATCAGCATCAGCATCAGCATCAGCATCGACTAGCATCAGCTACGAC
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如何读取此文件并提取DNA序列部分(ACCAGAGCGG...
)而不添加任何换行符,例如:
ACCAGAGCGGCACAGCAGCGACATCAGCACTAGCACTAGCATCAGCATCAGCATCAGCCTACATCATCACAGCAGCATCA
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也许不需要正则表达式?
foreach($array as $key => $value)
if (strlen($value) == 0)
unset($array[$key]);
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有这么多内置数组函数,有没有这样做?
寻找一些操作员(我猜是代替+?)
unsigned char bits = true + false + true + true + true; // 1 byte is sufficient
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成为以下位模式:
00010111
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然后,我如何检查if中的位模式
if (bits == 00010111)
Run Code Online (Sandbox Code Playgroud) 所以我得到了一个DNA序列.
ACCAGAGCGGCACAGCAGCGACATCAGCACTAGCACTAGCATCAGCATCAGCATCAGC
CTACATCATCACAGCAGCATCAGCATCGACATCAGCATCAGCATCAGCATCGACGACT
ACACCCCCCCCGGTGTGTGTGGGGGGTTAAAAATGATGAGTGATGAGTGAGTTGTGTG
CTACATCATCACAGCAGCATCAGCATCGACATCAGCATCAGCATCAGCATCGACGACT
TTCTATCATCATTCGGCGGGGGGATATATTATAGCGCGCGATTATTGCGCAGTCTACG
TCATCGACTACGATCAGCATCAGCATCAGCATCAGCATCGACTAGCATCAGCTACGAC
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我需要计算基数.
同样由于某种原因,它有时可以在同一个字符串中的大写或小写之间交替.
我想要所有的流量去:
|
V
我可以使用.htaccess或PHP中的东西,我正在使用zend框架.请注意我也有:
谢谢
在我班上我有成员职能:
const bool operator&&(const KinematicVariable &right) const {
return this->isUsed() && right.isUsed();
}
inline const bool isUsed() const { return this->_used; }
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然后我试试
if (k1 && k2 && k3)
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但我明白了
error: C2677: binary '&&' : no global operator found which takes type
'KinematicVariable' (or there is no acceptable conversion)
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