我想从MYSQL数据库中删除多行.我创建了这个delete.php文件来选择各种链接并使用复选框删除它们.
<html>
<head>
<title>Links Page</title>
</head>
<body>
<h2>Choose and delete selected links.</h2>
<?php
$dbc = mysqli_connect('localhost','root','admin','sample')
or die('Error connecting to MySQL server');
$query = "select * from links ORDER BY link_id";
$result = mysqli_query($dbc,$query)
or die('Error querying database');
$count=mysqli_num_rows($result);
?>
<table width="400" border="0" cellspacing="1" cellpadding="0">
<tr>
<td><form name="form1" method="post" action="">
<table width="400" border="0" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC">
<tr>
<td bgcolor="#FFFFFF"> </td>
<td colspan="3" bgcolor="#FFFFFF"><strong>Delete multiple links</strong> </td>
</tr>
<tr>
<td align="center" bgcolor="#FFFFFF">#</td>
<td align="center" bgcolor="#FFFFFF"><strong>Link ID</strong></td>
<td align="center" bgcolor="#FFFFFF"><strong>Link Name</strong></td>
<td align="center" …使用jQuery 1.9.1和HTML5,我想捕获只有特定类名的元素.
假设我有以下HTML代码:
<div>
<span class="req">A</span>
<span class="req notreq">B</span>
<span class="req notreq">C</span>
<span class="req">D</span>
</div>
我想只捕获<span>具有类的元素,req即值A和D.
使用jQuery,我可以使用console.log($('.req'));所有notreq值和所有值来捕获console.log($('span.req.notreq'))
我只需要req价值观.有帮助吗？