TL; DR我正在寻求帮助来实现下面的大理石图.目的是尽可能地对未排序的值进行排序,而无需等待扫描执行之间的时间.
我不是要求全面实施.欢迎任何指导.
我有一个异步慢(强制测试目的)扫描无限热观察.这是相关代码:
thread_1_scheduler = ThreadPoolScheduler(1)
thread = ExternalDummyService()
external_obs = thread.subject.publish()
external_obs \
.flat_map(lambda msg: Observable.just(msg).subscribe_on(thread_1_scheduler)) \
.scan(seed=State(0, None), accumulator=slow_scan_msg) \
.subscribe(log, print, lambda: print("SLOW FINISHED"))
external_obs.connect()
thread.start()
def slow_scan_msg(state, msg):
sleep(0.4)
return state \
._replace(count = state.count + 1) \
._replace(last_msg = msg)
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这是完整版:https://pyfiddle.io/fiddle/781a9b29-c541-4cd2-88ba-ef90610f5dbd
这是当前输出(值是随机生成的):
emitting Msg(count=0, timestamp=14.139175415039062)
emitting Msg(count=1, timestamp=6.937265396118164)
emitting Msg(count=2, timestamp=11.461257934570312)
emitting Msg(count=3, timestamp=13.222932815551758)
emitting Msg(count=4, timestamp=5.713462829589844)
SLOW st.count=0 last_msg.counter=0 ts=14.14
SLOW st.count=1 last_msg.counter=1 ts=6.94
SLOW st.count=2 last_msg.counter=2 ts=11.46
SLOW st.count=3 …Run Code Online (Sandbox Code Playgroud)