我想检查记录是否存在.
这是我尝试过的:
MainActivity.class
public void onTextChanged(CharSequence s, int start, int before, int count) {
System.out.println("Ontext changed " + new String(s.toString()));
strDocumentFrom = s.toString();
if(s.toString().isEmpty()){
} else {
try{
strTransactionDate = dbHelper.getTransactionDateByDocumentNumber(strDocumentFrom);
//strTotalAmount = dbHelper.getTotalAmountByDocumentNumber(strDocumentFrom);
//strVan = dbHelper.getVanByDocumentNumber(strDocumentFrom);
//etTransactionDate.setText(strTransactionDate);
//etTotalAmount.setText(strTotalAmount);
//Log.d("Van", "" + strVan);
//etVan.setText(strVan);
} catch (SQLiteException e) {
e.printStackTrace();
Toast.makeText(ReceivingStocksHeader.this,
"Document number does not exist.", Toast.LENGTH_SHORT).show();
}
}
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DBHelper.class
// TODO DISPLAYING RECORDS TO TRANSRCVHEADER
public String getTransactionDateByDocumentNumber(String strDocumentNumber){
String[] columns = new String[]{KEY_TRANSACTIONDATE};
Cursor c = myDataBase.query(TBL_INTRANS,
columns, …Run Code Online (Sandbox Code Playgroud) 我从db到dropdown的显示数据有困难.
这是我尝试过的:
Model.php
public function __construct()
{
parent::__construct();
}
function getAllGroups()
{
/*
$query = $this->db->get('location');
foreach ($query->result() as $row)
{
echo $row->description;
}*/
$query = $this->db->query('SELECT description FROM location');
foreach ($query->result() as $row)
{
echo $row->description;
}
//echo 'Total Results: ' . $query->num_rows();
}
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Controller.php这样
<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');
class Delivery_controller extends CI_Controller{
public function __construct()
{
parent::__construct();
$this->load->model('delivery_model');
}
public function index()
{
$data['title']= 'Warehouse - Delivery';
$this->load->view('include/header',$data);
$this->load->view('include/navbar',$data);
$this->load->view('delivery_view', $data);
$this->load->view('include/sidebar',$data); …Run Code Online (Sandbox Code Playgroud) 我想在我的绘画程序中加入一个颜色选择器.所以这里的任何人都已经做过这样的事情,请给我一些教程或一些代码来启动我.我真的需要得到添加这个的全部想法.我已经为绘图设置了画布,所以我想添加颜色选择器.欢迎任何想法.谢谢.
所以我现在所拥有的是:

但我想在左侧的文本框中包含图标搜索ICON SEARCH.
这是我的代码:
<form class="navbar-form pull-left form-search">
<select>
<option>Search patient by...</option>
<option name="fname">Firstname</option>
<option name="fname">Lastname</option>
<option name="fname">Last follow up</option>
</select>
<div class="input-append">
<input data-provide="typeahead" data-items="4" type="text"
class="span2 search-query">
<button class="btn">Search</button>
</div>
</form>
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那么任何想法如何实现这一目标?谢谢.
我已经为绘图设置了画布.我现在的问题是如何清除图纸.
试过这样做无济于事.
public void clear()
{
circlePath.reset();
mPath.reset();
// Calls the onDraw() method
//invalidate();
}
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请在这里查看整个代码:
https://gist.github.com/akosijiji/a29cca90bead2e5e35ad
真的很感激任何帮助.
我正在研究拖放应用程序,一切正常,但我看到了一个问题.我有3个ImageViews,其中两个是可拖动的对象,另一个是放置目标.每当我将物体放在掉落目标以外的任何位置时,它就完全消失了!
以下是我使用的代码:
ImageView iv1, iv2, iv3;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
initControls();
}
private void initControls() {
// TODO Auto-generated method stub
iv1 = (ImageView) findViewById (R.id.imageView1);
iv2 = (ImageView) findViewById (R.id.imageView2);
iv1.setTag("a");
iv2.setTag("b");
iv3 = (ImageView) findViewById (R.id.imageView3);
iv1.setOnTouchListener(new MyTouchListener());
iv2.setOnTouchListener(new MyTouchListener());
iv3.setOnDragListener(new MyDragListener());
}
private final class MyTouchListener implements OnTouchListener {
public boolean onTouch(View view, MotionEvent motionEvent) {
if (motionEvent.getAction() == MotionEvent.ACTION_DOWN) {
ClipData data = ClipData.newPlainText("", "");
DragShadowBuilder shadowBuilder = new View.DragShadowBuilder(view);
view.startDrag(data, shadowBuilder, …Run Code Online (Sandbox Code Playgroud) 我在下面的代码中有一个arrayoutofindexexception:
ImageView[] bObject = new ImageView[9];
private void getCorrectObject() {
List<Integer> objects = new ArrayList<Integer>();
objects.add(1);
objects.add(2);
objects.add(3);
objects.add(4);
objects.add(5);
objects.add(6);
objects.add(7);
objects.add(8);
objects.add(9);
Collections.shuffle(objects);
int correctObject = objects.get(0);
Log.d("test", String.valueOf(correctObject));
bObject[correctObject + 1].setImageResource(R.drawable.stage1_4_object1);
bObject[correctObject + 1].setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
goToNextQuestion();
}
});
}
//TODO initControls
private void initControls() {
bObject[0] = (ImageView) findViewById(R.id.bObject1Stage1_4);
bObject[0].setImageResource(R.drawable.stage1_4_object2);
bObject[1] = (ImageView) findViewById(R.id.bObject2Stage1_4);
bObject[1].setImageResource(R.drawable.stage1_4_object2);
bObject[2] = (ImageView) findViewById(R.id.bObject3Stage1_4);
bObject[2].setImageResource(R.drawable.stage1_4_object2);
bObject[3] = (ImageView) findViewById(R.id.bObject4Stage1_4);
bObject[3].setImageResource(R.drawable.stage1_4_object2);
bObject[4] = (ImageView) findViewById(R.id.bObject5Stage1_4);
bObject[4].setImageResource(R.drawable.stage1_4_object2); …Run Code Online (Sandbox Code Playgroud) 以下是所需的风格:

这是jsfiddle链接:这里
HTML:
<div class="photos">
<ul>
<li><span><a href="#"><img src="http://cdn.androidbeat.com/wp-content/uploads/2013/07/android.jpg" width="200" height="150" /></a></span>
<span>Android</span>
<a href="">See More...</a>
</li>
<li><a href="#"><img src="http://lotssports.com/wp-content/uploads/2013/07/zappy-android-300x300.jpg" width="200" height="150" /></a>
<span>Android</span>
<a href="">See More...</a>
</li>
<li><a href="#"><img src="http://cdn.androidbeat.com/wp-content/uploads/2013/07/android.jpg" width="200" height="150" /></a></li>
<li><a href="#"><img src="http://2.bp.blogspot.com/-65ZTcnMYW9c/TurVOon7PrI/AAAAAAAAA_s/07tBb3zCktI/s400/new%2Bprof.png" width="200" height="150" /></a></li>
</ul>
</div>
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CSS:
/* gallery display */
.photos {
display: block;
}
.photos ul {
list-style: none;
}
.photos ul li {
display: inline;
list-style: none;
float: left;
padding: 0 10px 0 0;
text-align:center;
}
.photos ul li span …Run Code Online (Sandbox Code Playgroud)