有没有办法获取和删除最后一行像poppython本机列表的方法?
我知道我可以在下面做.我只是想让它成为一条线.
df.ix[df.index[-1]]
df = df[:-1]
Run Code Online (Sandbox Code Playgroud) 我正在尝试通过Fiddler2本地代理捕获python SSL(HTTPS)连接.但我只有一个错误.
码
import requests
requests.get("https://www.python.org", proxies={"http": "http://127.0.0.1:8888", "https":"http:127.0.0.1:8888"},cert=r"FiddlerRoot.cer")
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错误
requests.exceptions.SSLError: [Errno 1] _ssl.c:510: error:14090086:SSL routines:
SSL3_GET_SERVER_CERTIFICATE:certificate verify failed
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任何人都可以告诉我如何修复错误,除了使验证错误?我已经在Windows 7系统上接受了"FiddlerRoot.cer",但没有任何改变.
我想获取pandas.Series.hist方法matplotlib.axes.AxesSubplot返回的值.有没有办法这样做?我在列表中找不到该属性.
import pandas as pd
import matplotlib.pyplot as plt
serie = pd.Series([0.0,950.0,-70.0,812.0,0.0,-90.0,0.0,0.0,-90.0,0.0,-64.0,208.0,0.0,-90.0,0.0,-80.0,0.0,0.0,-80.0,-48.0,840.0,-100.0,190.0,130.0,-100.0,-100.0,0.0,-50.0,0.0,-100.0,-100.0,0.0,-90.0,0.0,-90.0,-90.0,63.0,-90.0,0.0,0.0,-90.0,-80.0,0.0,])
hist = serie.hist()
# I want to get values of hist variable.
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我知道我可以得到直方图值np.histogram,但我想使用pandas hist方法.
我刚刚确认了Vec::contains工作原理。我在下面写了代码,看起来工作正常。
但我不知道它为什么有效,因为它比较&String类型。这是否意味着即使没有取消引用字符串比较也有效?
struct NewStruct {
string_vec: Vec<Option<String>>,
}
fn main() {
let mut mys = NewStruct {
string_vec: Vec::<Option<String>>::new(),
};
mys.string_vec.push(Some("new array".to_string()));
let ref_st = mys.string_vec.iter().filter(|o|o.is_some()).map(|o|o.as_ref().unwrap()).collect::<Vec<&String>>();
println!("result:{:?}", ref_st.contains(&&("some string".to_string())));
println!("result:{:?}", ref_st.contains(&&("new array".to_string())));
println!("Hello, world!");
f64::from(1234_u64 as i32);
}
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