小编Han*_*gbo的帖子

我添加了一个动作方法来查看控制器并按住Ctrl键将按钮拖动到故事板中的"退出"图标,并且成功创建了展开segue.但是当我触摸按钮时,展开segue不起作用(当前场景不起作用)导航到原始场景)并且没有触发动作方法.我不知道为什么.

这是动作方法

@interface HMCViewController2 : UIViewController
-(IBAction)return:(UIStoryboardSegue *)segue;
@end

@implementation HMCViewController2
...
-(IBAction)return:(UIStoryboardSegue *)segue{

}

@end

我将项目上传到谷歌驱动器.

首先,我将UISwipeGestureRecognizer附加到图像视图,无法触发操作方法.然后我附加UISwipeGestureRecognizer来查看控制器的视图,它运行良好.我不知道为什么.这是不起作用的代码

 - (void)viewDidLoad
{
    [super viewDidLoad];
    // Do any additional setup after loading the view.

    UISwipeGestureRecognizer *swipeRight=[[UISwipeGestureRecognizer alloc] initWithTarget:self action:@selector(swipeRightAction)];
    swipeRight.direction=UISwipeGestureRecognizerDirectionRight;
    //imageView is an outlet of image view
    [imageView addGestureRecognizer:swipeRight];
}

这是运行良好的代码

- (void)viewDidLoad
    {
        [super viewDidLoad];
        // Do any additional setup after loading the view.

    UISwipeGestureRecognizer *swipeRight=[[UISwipeGestureRecognizer alloc] initWithTarget:self action:@selector(swipeRightAction)];
    swipeRight.direction=UISwipeGestureRecognizerDirectionRight;
    //imageView is an outlet of image view
    [self.view addGestureRecognizer:swipeRight];
}

我在Mac上用OS X 10.9运行节点服务器.这是代码

var http = require('http');

http.createServer(function (request, response) {
  response.writeHead(200, {'Content-Type': 'text/plain'});
  response.end('Hello World\n');
}).listen(3000, '0.0.0.0');

console.log('Server running at http://192.168.1.120:3000/');

我可以在我的Mac上使用Safari来访问服务器http://192.168.1.120:3000/.但是当我用我的iPhone访问服务器时,它失败了.我的Mac的防火墙已关闭,而我的iPhone与Mac的WiFi相同.

我只知道CCNode的旋转属性可能与它有关.但我想水平翻转一个精灵,而不是旋转.

当我不使用纹理图集时,一切都运行正常.但是当我使用纹理图集时,animateWithTextures不起作用而且什么都没有出现.这是我的代码

SKTexture *spaceshipTexture = [SKTexture textureWithImageNamed:@"monkey.png"];
SKSpriteNode *spaceship = [SKSpriteNode spriteNodeWithTexture:spaceshipTexture];
spaceship.position = CGPointMake(0,0);
spaceship.anchorPoint = CGPointMake(0,0);
[self addChild: spaceship];

NSMutableArray *images=[NSMutableArray arrayWithCapacity:14];
for (int i=1; i<=14; i++) {
    NSString *fileName=[NSString stringWithFormat:@"%dShuGuangx.png",i];
    SKTexture *tempTexture=[SKTexture textureWithImageNamed:fileName];
    [images addObject:tempTexture];
}
NSLog(@"count %d",images.count);
SKAction *walkAnimation = [SKAction animateWithTextures:images timePerFrame:0.1];
[spaceship runAction:walkAnimation];

在我的视图控制器中,我向self.view添加了一个UITapGestureRecognizer.我在self.view上添加了一个小视图.当我点击小视图时,我不想在self.view中触发UITapGestureRecognizer事件.这是我的代码,它不起作用.

    - (void)viewDidLoad {
    [super viewDidLoad];

    UITapGestureRecognizer *_tapOnVideoRecognizer = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(toggleControlsVisible)];

    [self.view addGestureRecognizer:_tapOnVideoRecognizer];

    UIView *smallView=[[UIView alloc] initWithFrame:CGRectMake(0, 0, 200, 200)];
    smallView.backgroundColor=[UIColor redColor];
    smallView.exclusiveTouch=YES;
    smallView.userInteractionEnabled=YES;

    [self.view addSubview:smallView];
    }

    - (void)toggleControlsVisible
    {
        NSLog(@"tapped");
    }

当我点击小视图时,它仍会在self.view中触发点击事件.Xcode记录"轻拍".如何拦截从smallView到self.view的手势事件？

我编写了一个简单的iOS程序来使用React Native显示图像.

'use strict';

var React = require('react-native');
var {
  Image
} = React;

var styles = React.StyleSheet.create({

  base: {
    height: 400,
    width: 400 
}
});

class SimpleApp extends React.Component {
  render() {
    return (
    <Image
    style={styles.base}
    source={require('image!k')}
    //source={{uri: 'http://news.xinhuanet.com/world/2015-05/09/127782089_14311512601821n.jpg'}}
      /> 
    )
  }
}

React.AppRegistry.registerComponent('SimpleApp', () => SimpleApp);

但是我从iPad屏幕上收到了消息:

"Failed to print error:","'undefined' is not an object (evaluating 'stackString.split')"

当我更改代码以使用图像网址时

//source={require('image!k')}
source={{uri: 'http://news.xinhuanet.com/world/2015-05/09/127782089_14311512601821n.jpg'}}

我只得到一个红色的矩形边框.

当我使用另一个js文件时,一切运行良好."Hello World"可以在iPad屏幕上显示.

'use strict';

var React = require('react-native');
var {
  Text,

} = React;


class SimpleApp …

我使用WKWebView加载网页。当用户单击网页中的按钮时，我的网页将打开一个自定义架构URL（例如asfle：// download？media_id = 1）。我使用KVO观察WKWebView的URL属性以获取URL。它在iOS 9中很好用，但在iOS 10中不起作用。我无法获取URL。我使用Xcode 8，Swift 2.3。

override func viewDidLoad() {
        super.viewDidLoad()

        webView.addObserver(self, forKeyPath: "URL", options: .New, context: nil)
    }

override func observeValueForKeyPath(keyPath: String?,
                                  ofObject object: AnyObject?,
                                           change: [String : AnyObject]?,
                                                  context: UnsafeMutablePointer<Void>)
    {
        print("url?\(webView.URL)")
    }

在iOS 9中，它可以打印网址。但是在iOS 10中，仅打印网站的url，当用户触摸网页中的按钮时，不会打印任何内容。

我想为UIView添加摇动效果,但我失败了.我的代码也是

    CGRect rectL=CGRectMake(473, 473, 88, 88);
    CGRect rectR=CGRectMake(493, 473, 88, 88);
    NSValue *valueL = [NSValue value: &rectL
                         withObjCType:@encode(CGRect)];
    NSValue *valueR = [NSValue value: &rectR
                        withObjCType:@encode(CGRect)];
    NSArray *firstArray=@[valueL,valueR,valueL,valueR,valueL,valueR,valueL,valueR];

    [UIView animateWithDuration:2 animations:^{
        CAKeyframeAnimation * theAnimation;

        // Create the animation object, specifying the position property as the key path.
        theAnimation=[CAKeyframeAnimation animationWithKeyPath:@"frame"];
        theAnimation.values=firstArray;
        theAnimation.duration=5.0;
        theAnimation.calculationMode= kCAAnimationLinear;
        // Add the animation to the layer.
        [self.boView.layer addAnimation:theAnimation forKey:@"frame"];//boView is an outlet of UIView
    }completion:^(BOOL finished){

    }];

当我运行代码时,视图仍然没有抖动.为什么？

UPDATE

我必须使用关键帧动画,因为在视图抖动之后,它需要移动到另一个地方,然后摇动然后停止.这是我编辑的代码,但它仍然不起作用.为什么？

    CGRect rectL=CGRectMake(463, 473, 88, 88);
    CGRect rectR=CGRectMake(503, …

我在iOS项目中使用FMDB.但是当我用FMDB读取ROWID时,Xcode日志"警告:我找不到名为'rowid'的列."

...
 //Create database
 NSString *documentsPath = [NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES) objectAtIndex:0];
    NSString *dbPath = [documentsPath   stringByAppendingPathComponent:@"bookmarksDatabase.sqlite"];

    BOOL needCreateTable = ![[NSFileManager defaultManager] fileExistsAtPath:dbPath];
    FMDatabase *db = [FMDatabase databaseWithPath:dbPath];
    [db open];
    if (needCreateTable) {

        [db executeUpdate:@"CREATE TABLE bookmarks (title TEXT ,url TEXT ,folderID INTEGER ,locationIndex INTEGER)"];
    }
    else
    {
        [self reloadBookmarkDatabase:db];

    }

        [db close];

   ...
   //Read database. Only "ROWID" column can't find.
FMResultSet *results = [db executeQuery:@"SELECT * FROM bookmarks ORDER BY locationIndex"];
    while([results next]) {
        BookmarkData *temp  = [[BookmarkData alloc] initWithID:[results …

我正在iOS项目中使用VLCKit(MobileVLCKit.framework).起初一切都很好.然后我添加一些C++代码,所以一些文件是.mm文件.当我编译时,它失败了.Xcode日志

Undefined symbols for architecture armv7:
  "std::runtime_error::runtime_error(std::string const&)", referenced from:
      libebml::CRTError::CRTError(std::string const&, int) in MobileVLCKit(StdIOCallback.o)
  "std::ostream& std::ostream::_M_insert<void const*>(void const*)", referenced from:
      libebml::IOCallback::writeFully(void const*, unsigned long) in MobileVLCKit(IOCallback.o)
      libebml::IOCallback::readFully(void*, unsigned long) in MobileVLCKit(IOCallback.o)
  "std::runtime_error::runtime_error(std::string const&)", referenced from:
      libebml::IOCallback::writeFully(void const*, unsigned long) in MobileVLCKit(IOCallback.o)
      libebml::IOCallback::readFully(void*, unsigned long) in MobileVLCKit(IOCallback.o)
      "VTT for std::basic_stringstream<char, std::char_traits<char>, std::allocator<char> >", referenced from:
...

我不知道为什么以及如何解决这个问题.

我想点击UICollectionView的单元格，该单元格变为半透明。

    - (void)collectionView:(UICollectionView *)collectionView
didSelectItemAtIndexPath:(NSIndexPath *)indexPath
{
    GLEpisodeCell *cell=[collectionView dequeueReusableCellWithReuseIdentifier:[GLEpisodeCell identifier] forIndexPath:indexPath];//GLEpisodeCell is subclass of UICollectionViewCell
    cell.alpha=0.5;
    cell.contentView.alpha=0.5;
}

但这是行不通的。细胞仍然不透明。