小编Has*_*asT的帖子

我有一个简单的datable https://jsfiddle.net/ptwgxpzu/27/

JS：

    var dataSet = [
    ["data/rennes/", "Rennes", "rennes.map"],
    ["data/nantes/", "Nantes", "nantes.map"],
    ["data/tours/", "Tours", "tours.map"],
    ["data/bordeaux/", "Bordeaux", "bordeaux.map"],
    ["data/limoges/", "Limoges", "limoges.map"],
    ["data/troyes/", "Troyes", "troyes.map"]
];


var table = $('#maptable').DataTable({
    "data": dataSet,
    "paging": false,
    "columns": [{
        title: "Download"
    }, {
        title: "Name"
    }, {
        title: "File Name"
    }],

    "columnDefs": [{
            "targets": [0], // Download
            "visible": true,
            "searchable": false,
            "bSortable": false
        }, {
            "targets": [1], // Name
            "visible": true,
            "searchable": true
        }, {
            "targets": [2], // File name
            "visible": true,
            "searchable": …

我在 PostgreSQL 数据库中有表“A”：

name     fullname
A         A,I,A
B         B,B,S,B
D         D,D,S,E,D
E         E,E,D,G,E
F         F,F,G,F
G         G,E,G,F,G,H,N,G

如何接收带有列“正确名称”（全名）的表“B”，其中每行中没有来自“名称”字段的匹配子字符串：

name  correctname
A      I
B      S
D      S,E
E      D,G
F      G
G      E,F,H,N

数据样本：

CREATE TABLE test(name TEXT, fullname TEXT);

INSERT INTO test(name, fullname) VALUES('A','A,I,A');
INSERT INTO test(name, fullname) VALUES('B','B,B,S,B');
INSERT INTO test(name, fullname) VALUES('D','D,D,S,E,D');
INSERT INTO test(name, fullname) VALUES('E','E,E,D,G,E');
INSERT INTO test(name, fullname) VALUES('F','F,F,G,F');
INSERT INTO test(name, fullname) VALUES('G','G,E,G,F,G,H,N,G');

谢谢！