小编Eri*_*ric的帖子

我正在尝试从我正在开发的API上运行的一组测试中捕获异常,并且我使用Guzzle来使用API​​方法.我已经将测试包装在try/catch块中,但它仍然会抛出未处理的异常错误.按照文档中的描述添加事件侦听器似乎没有做任何事情.我需要能够检索具有500,401,400的HTTP代码的响应,实际上任何不是200的响应,因为如果系统不起作用,系统将根据调用的结果设置最合适的代码.

当前的代码示例

foreach($tests as $test){

        $client = new Client($api_url);
        $client->getEventDispatcher()->addListener('request.error', function(Event $event) {        

            if ($event['response']->getStatusCode() == 401) {
                $newResponse = new Response($event['response']->getStatusCode());
                $event['response'] = $newResponse;
                $event->stopPropagation();
            }            
        });

        try {

            $client->setDefaultOption('query', $query_string);
            $request = $client->get($api_version . $test['method'], array(), isset($test['query'])?$test['query']:array());


          // Do something with Guzzle.
            $response = $request->send();   
            displayTest($request, $response);
        }
        catch (Guzzle\Http\Exception\ClientErrorResponseException $e) {

            $req = $e->getRequest();
            $resp =$e->getResponse();
            displayTest($req,$resp);
        }
        catch (Guzzle\Http\Exception\ServerErrorResponseException $e) {

            $req = $e->getRequest();
            $resp =$e->getResponse();
            displayTest($req,$resp);
        }
        catch (Guzzle\Http\Exception\BadResponseException $e) {

            $req = $e->getRequest();
            $resp …