小编Mun*_*ren的帖子

我在这里表达了一个常见的问题.但我无法从各地获得解决方案.这是我的代码:如果row不为空,则渲染代码页,否则执行另一个操作.

app.get('/send',function(req,res){
  var code=req.query['c']; // -- get request from input
  connection.query("use mynum");
  var strQuery = "select * from table WHERE code='"+code+"' LIMIT 1";   
  connection.query( strQuery, function(err, rows){
    if(err) {
      throw err;
    }else{
      if(rows.length==1){
        res.render('pages/code', {code : rows[0].code});
        connection.end();
        res.end();
      }else {
        // here is some actions
      }
    }
  });
  res.end();
});

堆栈跟踪:

Error: Can't set headers after they are sent.
at ServerResponse.OutgoingMessage.setHeader (http.js:690:11)
at ServerResponse.header (C:\wamp\www\vin_number\node_modules\express\lib\re
sponse.js:666:10)
at ServerResponse.res.contentType.res.type (C:\wamp\www\vin_number\node_modu
les\express\lib\response.js:532:15)
at ServerResponse.send (C:\wamp\www\vin_number\node_modules\express\lib\resp
onse.js:121:14)
at fn (C:\wamp\www\vin_number\node_modules\express\lib\response.js:900:10)
at View.exports.renderFile …

这是我的部分代码:

 <div id="account"><a href="@routes.Contacts.blank()">Contact</a></div>` 

而不是它,我使用上面的代码

<div id="account"><a href="account.html">Contact</a></div>

所以,我想在索引页面上直接加载静态html页面.
请帮我.坦克