小编SKa*_*aul的帖子

我尝试进行切入点,以记录SQL查询

  @Before("execution(* org.springframework.jdbc.core.JdbcTemplate.*(String, ..))")
public void logSQLQueries() {
        System.out.println("@@");
    }

我想在这里实现代码; http://www.gotoquiz.com/web-coding/programming/java-programming/log-sql-statements-with-parameter-values-filled-in-spring-jdbc/

但我明白了

java.lang.IllegalArgumentException: Can not set org.springframework.jdbc.core.JdbcTemplate field com.xyz.abc.dao.ABCDaoImpl.jdbcTemplate to com.sun.proxy.$Proxy53

我在我的*-servlet.xml中创建了jdbcTemplate bean,并在我所有的DAO中自动启用了它.工作得非常好,但添加切入点会产生异常.有任何想法吗 ？？

我正在尝试以下代码:http://www.dineshonjava.com/2012/12/spring-mvc-with-hibernate-crud-example.html#.Uus0bvnoSGc sdnext-servlet.xml如下

<beans xmlns:context="http://www.springframework.org/schema/context" xmlns:tx="http://www.springframework.org/schema/tx" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://www.springframework.org/schema/beans" xsi:schemalocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-3.0.xsd">

<context:property-placeholder location="classpath:resources/database.properties">
</context:property-placeholder>
<context:component-scan base-package="com.dineshonjava">
</context:component-scan>

<tx:annotation-driven transaction-manager="hibernateTransactionManager">
</tx:annotation-driven>

<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver" id="jspViewResolver">
 <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"></property>
 <property name="prefix" value="/WEB-INF/views/"></property>
 <property name="suffix" value=".jsp"></property>
</bean>

<bean class="org.springframework.jdbc.datasource.DriverManagerDataSource" id="dataSource">
 <property name="driverClassName" value="${database.driver}"></property>
 <property name="url" value="${database.url}"></property>
 <property name="username" value="${database.user}"></property>
 <property name="password" value="${database.password}"></property>
</bean>

<bean class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean" id="sessionFactory">
 <property name="dataSource" ref="dataSource"></property>
 <property name="annotatedClasses">
  <list>
   <value>com.dineshonjava.model.Employee</value>
  </list>
 </property>
 <property name="hibernateProperties">
 <props>
  <prop key="hibernate.dialect">${hibernate.dialect}</prop>
  <prop key="hibernate.show_sql">${hibernate.show_sql}</prop>
  <prop key="hibernate.hbm2ddl.auto">${hibernate.hbm2ddl.auto}  </prop>    
        </props>
      </property>
</bean> …

我试图使用JPA与Spring MVC,mySql.我从这里了解JPA和Hibernate有什么区别？JPA可以单独使用,但是大多数Web资源都将其描述为仅需要实现的规范.那么我可以在没有EclipseLink,Hibernate等持久性提供程序的情况下使用JPA,如果是,那么如何？

我需要重定向到另一个页面上点击提交并调用一个函数进行ajax调用.这就是我所拥有的:

$('#submitButton').click(function() {

window.location.href = "otherPage";
displayData();
});

另外,我尝试的另一种方法是使用在otherPage上设置表单字段

var elem = window.document.getElementById(field);
elem.value = "new-value";

这样我就可以在otherPage上调用提交按钮的事件处理程序,但它不起作用.请让我知道我错在哪里.